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mafiozo [28]
2 years ago
14

Is (2,3) a solution to the system of inequalities 4x+3y<20 10x+y>10

Mathematics
2 answers:
stiks02 [169]2 years ago
7 0
Yes it is a solution because if you take the equation and plug the point in for the x and y :

4 (2) + 3 (3) < 20 
 8 + 9 < 20 
17 < 20
which is true

10 (2) + (3) > 10
20 + 3> 10
23>10
which is also true
defon2 years ago
3 0
Hope this helps..... :)

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Wittaler [7]

The US equivalent of "liters to meters" would be something like
"quarts to yards", which is equally meaningless.

Liters and meters don't even measure the same thing.  Liters describe
volume, whereas meters describe length or distance.    They don't convert
to each other .

If volume units could be converted to length units, then you (or somebody
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6 0
3 years ago
Determine whether (2, - 1) and (-4, 2) satisfy the inequality 2x – 3y &gt; 4.
Xelga [282]

Answer:

emngtehrge

Step-by-step explanation:

egrbrrg

7 0
3 years ago
Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.
sp2606 [1]

Answer:

(A) The odds that the taxpayer will be audited is approximately 0.015.

(B) The odds against these taxpayer being audited is approximately 65.67.

Step-by-step explanation:

The complete question is:

Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.

A. What are the odds that the taxpayer will be audited?

B. What are the odds against such tax payer being audited?

Solution:

The proportion of U.S. taxpayers who were audited is:

P (A) = 0.015

Then the proportion of U.S. taxpayers who were not audited will be:

P (A') = 1 - P (A)

        = 1 - 0.015

        = 0.985

(A)

Compute the  odds that the taxpayer will be audited as follows:

\text{Odds of being Audited}=\frac{P(A)}{P(A')}

                                    =\frac{0.015}{0.985}\\\\=\frac{3}{197}\\\\=0.015228\\\\\approx 0.015

Thus, the odds that the taxpayer will be audited is approximately 0.015.

(B)

Compute the odds against these taxpayer being audited as follows:

\text{Odds against Audited}=\frac{P(A')}{P(A)}

                                    =\frac{0.985}{0.015}\\\\=\frac{3}{197}\\\\=65.666667\\\\\approx 65.67

Thus, the odds against these taxpayer being audited is approximately 65.67.

8 0
3 years ago
Divide 20m^2n^3 - 10m^2n by 5mn
Sonja [21]

\frac{20 {m}^{2} {n}^{3}  - 10 {m}^{2}n  }{5mn}  \\  =   \frac{5mn(4m {n}^{2} - 2m) }{5mn}  \\  = 4 {m}^{2} n - 2m \\  = 2m(2mn - 1)

Hope this helps. - M
6 0
3 years ago
I need help. I’ll seriously make you brainly
ser-zykov [4K]

Answer:

a = 12

Step-by-step explanation:

add 2 to each side

5a/3 = a/4 + 17

distribute 12 to remove fractions

20a = 3a + 204

17a = 204

a = 12

7 0
2 years ago
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