Solution,
Mass of Mg - 21gm
molar mass of Mg - 24gm
moles = Given mass/ Molar mass
moles = 21/24 = 0.875
1 mole of Mg produce 1 mole of H2 gas
so 0.875 mole of Mg will produce 0.875 moles of H2 gas
One mole of H2 gas = 22.4 litre
0.875 mole of H2 gas = 0.875×22.4
0.875 mole of H2 gas = 19.60 litre
So the nearest ANSWER is Option four 19.37 litre.
In order to find the molarity of the solution, we first require the moles of acetic acid added. For this,we need the mass which is:
Mass = volume * density
Mass = 50 * 1.05
Mass = 52.5 grams
Moles = mass / molecular weight
Moles = 52.5 / 60.05
Moles = 0.874 mol
Next, we know that the molarity of a solution is:
Molarity = moles / liter
Molarity = 0.874 / 0.5
Molarity = 1.75 M
Use PV=nRT to solve the equation. You need to solve for n (number of moles). Don’t forget to convert the temperature to kelvins by adding 25+273. Use 0.082057 for R.
Answer:
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