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Trava [24]
1 year ago
5

If 25.0 g NO are produced, how many grams of nitrogen gas are used?

Chemistry
1 answer:
ivanzaharov [21]1 year ago
7 0

Based on the assumption that the reaction involves N and O to produce NO, if 25.0 g of NO are produced, the amount of N gas used would be 11.66 grams

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

       N + O ---------> NO

Mole ratio of N to NO is 1:1

Mole of 25.0 g of NO = 25/30.01 = 0.833 moles

Equivalent mole of N = 0.833 moles

Mass of 0.833 moles N = 0.833 x 14 = 11.66 grams

More on stoichiometric calculations can be found here: brainly.com/question/8062886

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Give the empirical formula for C↓8H↓8
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Answer:

Empirical formula of  C₈H₈ =  CH

Explanation:

Data Given:

Molecular Formula = C₈H₈

Empirical Formula = ?

Solution

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule

        C₈H₈ Consist of  Carbon (C), and Hydrogen (H)

Now

Look at the ratio of these two atoms in the compound

                         C : H

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Divide the ratio by two to get simplest ratio

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                       8/8 : 8/8

                         1   :  1

So for the empirical formula is the simplest ratio of carbon to hydrogen 1 : 1

So the empirical formula will be

                     Empirical formula of  C₈H₈ =  CH

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