Answer:
journal entry are given below
carrying value = $4000 and cash received is $2000
Explanation:
given data
delivery van cost = $20,000
accumulated depreciation = $16,000
Annual depreciation = $2,000
solution
journal entry are
date title debit credit
December 29, 2019 Cash $2000
Accumulated depreciation $16000
Delivery van $20000
note that
here carrying value is = $20000 - $16000
carrying value = $4000
and cash received is $2000
Answer:
If I bougth the Machine at 14% interest.
This purchase is not justified
Depreciation expenses and credit interest are greater than the income generated
Explanation:
Machine 360000
Adittional cost 20000
Final Cost 380000
Salvage Value 73000
Machine value for depreciation 307000
year 1 307000 61400 245600
year 2 245600 61400 184200
year 3 184200 61400 122800
year 4 122800 61400 61400
year 5 61400 61400 0
Period Payment Capital Interest Loan
360000
1 104.862 54.462 50.400 305.538
2 104.862 62.087 42.775 243.451
3 104.862 70.779 34.083 172.672
4 104.862 80.688 24.174 91.984
5 104.862 91.984 12.878 0
Depreciation 307000
Interes 164.310
Expenses 471.310
Revenue 430.000
Answer: $15600
Explanation:
To calculate the amount of the Payroll Department's cost that is allocated to the Assembly Department goes thus:
First we need to calculate the allocation rate which will be:
= $300,000/25,000
= $12.
Then, the departmental cost will be:
= Payroll checks × Allocation rate
= 1,300 × $12
= $15,600.
Therefore, the amount of the Payroll Department's cost that is allocated to the Assembly Department is $15600.
Answer:
P0 = $66.6429 rounded off to $66.64
Option c is the correct answer
Explanation:
Using the two stage growth model of dividend discount model, we can calculate the price of the stock today. The DDM values a stock based on the present value of the expected future dividends from the stock. The formula to calculate the price of the stock today is,
P0 = D0 * (1+g1) / (1+r) + D0 * (1+g1)^2 / (1+r)^2 + ... + D0 * (1+g1)^n / (1+r)^n + [(D0 * (1+g1)^n * (1+g2) / (r - g2)) / (1+r)^n]
Where,
- g1 is the initial growth rate
- g2 is the constant growth rate
- r is the required rate of return
P0 = 2* (1+0.2) / (1+0.1) + 2 * (1+0.2)^2 / (1+0.1)^2 + 2 * (1+0.2)^3 / (1+0.1)^3
+ 2 * (1+0.2)^4 / (1+0.1)^4 + 2 * (1+0.2)^5 / (1+0.1)^5 +
[(2 * (1+0.2)^5 * (1+0.04) / (0.1 - 0.04)) / (1+0.1)^5]
P0 = $66.6429 rounded off to $66.64
