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GrogVix [38]
3 years ago
15

Tris is a weak base. The basic form of tris can be written tris0 and the protonated (conjugate acid) form can be written tris. T

he pKa of tris is 8.1. a. What is the ratio of the basic and the acidic forms of tris at pH 6.1? b. What is the useful buffering range of tris?
Chemistry
1 answer:
Arada [10]3 years ago
8 0

Answer:

a) [Tris0] : [Tris] = 1 : 100

b) Range = 7.1 to 9.1

Explanation:

a) Calculation of ratio of the basic and the acidic forms of tris

pH of a buffer is calculate using Henderson-Hasselbalch equation

pH = pKa+log\frac{Salt}{Acid}

Conjugate acid of Tris dissociated as

Tris \leftrightharpoons Tris0 + H^+

For tris,

Salt or Basic form = tris0

Acid or Acidic form = Tris

pKa = 8.1

pH = 6.1

pH = pKa+log\frac{Tris0}{Tris}

6.1 = 8.1+log\frac{Tris0}{Tris}

log\frac{Tris0}{Tris} = -2

\frac{Tris0}{Tris} = antilog (-2)

\frac{Tris0}{Tris} = 10^{-2}

[Tris0] : [Tris] = 1 : 100

b) Range of Tris

Range of any buffer is:

From (pKa -1) to (pKa+1)

So, range of Tris is:

From (8.1 - 1) to (8.1 +1)

or from 7.1 to 9.1

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Explanation:Please see attachment for explanation

6 0
3 years ago
It took 4.5 minutes for 1.0 l helium to effuse through a porous barrier. how long will it take for 1.0 l cl2 gas to effuse under
serious [3.7K]
When The rate of effusion is inversely proportional to the √molar mass of the substance.
and we have R(He) = 1L / 4.5 min so,
R(He)/R(Cl2) = (molar mass of Cl2/ molar mass of He)^0.5
and when we have the molar mass of Cl2 = 70.9  & the molar mass of He = 4
so by substitution:
(1L/4.5 min)/ R(Cl2) = (70.9 / 4)^0.5
(1L/4.5 min) / R(Cl2) = 4.21
∴R(Cl2) = (1L/4.5 min) / 4.21 = 1L/ (4.5*4.21)min = 1 L / 18.945 min
∴Cl2 will take 18.945 min for 1 L to effuse under identical conditions

4 0
4 years ago
Draw the Lewis structure (including all lone pair electrons) for one isomer of the molecular formula C3H8O.
Andreyy89

Answer:

Here's how I would do it.

Explanation:

A Lewis structure shows the valence electrons surrounding the atoms.

1. Identify the central atoms

The central atoms are the least electronegative atoms (C).

I chose as my central atoms a chain of four C atoms: C-C-C-C

I stuck the most electronegative atom (O) at the end of the chain:

C-C-C-C-O

2. Complete the structure

The hydrogen atoms must be terminal. Add enough to give every atom an octet.

You should get a structure like the one below

3 0
3 years ago
) A children’s liquid cold medicine has a density of 1.23 g/mL. If a child is to take 2.5 tsp in a dose, what is the mass in gra
vekshin1

The relation between density and mass and volume is

Density=\frac{Mass}{volume}

the dose required is 2.5 tsp

each tsp contain 5mL

So dose required in mL = 2.5 X 5 = 12.5 mL

the mass will be calculated using following formula

Mass=DensityXvolume

Mass=1.23\frac{g}{mL}X12.5mL= 15.38g

The mass of dose in grams will be 15.38 g


5 0
3 years ago
What is the mass of 0.2 mole of sodium.
FromTheMoon [43]
Therefore 0.2 moles of sodium (Na) contains 12.046×1023atoms in it.
3 0
3 years ago
Read 2 more answers
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