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Vlada [557]
3 years ago
8

Suppose that a chemist is mixing two acid​ solutions, one of 20​% concentration and the other of 30​% concentration. Which of th

e following concentrations could not be​ obtained?
1. 22​%,
2. 24​%,
3. 28​%,
4. 34​%
Mathematics
1 answer:
Pani-rosa [81]3 years ago
5 0

Answer:

4. 34%

Step-by-step explanation:

By mixing 20% and 30%, it will be between 20 and 30, like 22, 24 or 28. You would need a higher concentration than 30 to mix in to get 34%.

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Find the equation of the line through the points (3,-4) and (0,2) answer in slope intercept form
zhannawk [14.2K]

Answer:

y= -2x+2.

Step-by-step explanation:

1) according to the condition interception is '2' (point (0;2));

2) slope is: (2+4)/(0-3)= -2;

3) finally the required equation is: y=-2x+2.

P.S. the suggested option is not the only one.

4 0
2 years ago
What’s the area of the figure below?
TEA [102]

Answer:

482.5 ft^2.

Step-by-step explanation:

The figure can be regarded as a rectangle with a triangle cut out of one corner.

The base of the triangle = 25-20 = 5 in and the height = 20 - 13 = 7 in.

The required area = area of rectangle - area of triangle

= 25*20 - 1/2 * 5 * 7

= 500 - 17.5

= 482.5 ft^2

5 0
3 years ago
Read 2 more answers
Make x subject of the formula in y=2x+p​
zaharov [31]

Answer:

(y-p)/2

Step-by-step explanation:

take p to the left side. + p becomes - p. Now divide the whole thing by 2

8 0
3 years ago
Read 2 more answers
Select all that are true
sertanlavr [38]
A=-1, b=2 I hope this helped. Please please please if you like my answer mark Brainly:)
3 0
2 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
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