All categories

4 years ago

Find the most important variable in the problem,

Mathematics

1 answer:

qaws [65]4 years ago

8 0

Answer:

I believe the answer is 261 miles an hour.

Step-by-step explanation:

783 divided by 3 is equal to 261. Please let me kow if you got the answer wrong or right. Hope this helps.

You might be interested in

2r = 72 please help me

noname [10]

you divide 72 by 2 to get r by itself and get 36

so r=36

6 0

3 years ago

Read 2 more answers

Cristian comió un 3/8 de pizza y Adriana comió 1/4 de la misma pizza. ¿Quién comió mas?

Oduvanchick [21]

Cristian! Si ocupas el resultado es 0.375 (el de cristian)

3 0

3 years ago

Paul,Linda,and Aaron make homemade cards. Paul can make 1 card for every 3 cards Linda makes. Linda can make 3 cards for every 2

dimaraw [331]

Answer:

Linda makes 72 more cards than Paul

during the week

Step-by-step explanation:

Here, we want to know how many cards Linda makes than Paul during the week.

We proceed as follows;

From the question;

If Paul makes 1 card, then Linda has made three

Now let’s get their relationship with Aaron;

If Aaron makes 2 cards , Linda has made three

Now since Aaron made 72 cards, Let’s say Linda has made x cards

Let’s get the value of x now

To get the value of x, we simply cross multiply;

2 - 3

72 - x

2 * x = 3 * 72

x = (3 * 72)/2 = 108 cards

Now recall , for every 3 cards of Linda, Paul made only 1;

So the number of cards Paul will make if Linda makes 108 will be 108/3 = 36

So the number of more cards that Linda makes than Paul during the week will be ; 108 -36 = 72 cards

3 0

4 years ago

The number of typing errors made by a typist has a Poisson distribution with an average of seven errors per page. If more than s

Aleks [24]

Answer:

0.599 is the probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

We are given the following in the question:

The number of typing errors made by a typist has a Poisson distribution.

$\lambda =7$

The probability is given by:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

We have to find the probability that a randomly selected page does not need to be retyped

P(less than or equal to 7 mistakes in a page)

$P( x \leq 7) = P(x =1) + P(x=1) +...+ P(x=6) + P(x = 7)\\\\= \displaystyle\frac{7^0 e^{-7}}{0!} + \displaystyle\frac{7^1 e^{-7}}{1!} +...+ \displaystyle\frac{7^6 e^{-7}}{6!} + \displaystyle\frac{7^7 e^{-7}}{7!} \\\\= 0.59871\approx 0.599$

Thus, 0.599 is the probability that a randomly selected page does not need to be retyped.

4 0

4 years ago

Which is a counterexample to the conjecture? The product of any two consecutive integers is a composite number.

Colt1911 [192]

C is the answer, because 2 is prime.

8 0

3 years ago