A city has 5 new houses for every 9 old houses. If there are 35 new houses in the city, how many old houses are there?
2 answers:
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Answer: Our required probability would be 0.70.
Step-by-step explanation:
Since we have given that
Number of players = 14
Number of players have recently taken a performance enhancing drug = 3
Number of players have not recently taken a performance enhancing drug = 14-3=11
Number of members chosen randomly = 5
We need to find the probability that at least one of the tested players is found to have taken a performance enhancing drug.
P(Atleast 1) = 1 - P(none is found to have taken a performance enhancing drug)
So, P(X≥1)=1-P(X=0)
Hence, our required probability would be 0.70.
Answer:
In order to maximize the last equation we can derivate the function in term of x and we got:
And setting this derivate equal to 0 we got:
And solving for x we got:
And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:
Step-by-step explanation:
For this case we have the following function for the profit:
And we can rewrite this expression like this:
In order to maximize the last equation we can derivate the function in term of x and we got:
And setting this derivate equal to 0 we got:
And solving for x we got:
And for this case the value that maximize the profit would be x =95 and the corresponding profit would be: