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2 years ago

Solve the equation. S- (- 20) = 19

Mathematics

1 answer:

PtichkaEL [24]2 years ago

3 0

Answer:

s = -1

Explanation:

s − (−20) = 19

[ Simplify both sides of the equation ]

s + 20 = 19

[ Subtract 20 from both sides ]

s + 20 − 20 = 19 − 20

s = −1

- PNW

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HELP ASAP: what is another way to write to 72-(-25)? My answer ***

timurjin [86]

Answer: none

Step-by-step explanation:

72-(-25) = 72+25 = 97

8 0

2 years ago

Given the midpoint and one endpoint of a line segment, find the other endpoint.

neonofarm [45]

Answer:

(-12 , 2)

Step-by-step explanation:

GIVEN :-

Co-ordinates of one endpoint = (-4 , -10)
Co-ordinates of the midpoint = (-8 , -4)

TO FIND :-

Co-ordinates of another endpoint.

FACTS TO KNOW BEFORE SOLVING :-

Section Formula :-

Let AB be a line segment where co-ordinates of A = (x¹ , y¹) and co-ordinates of B = (x² , y²). Let P be the midpoint of AB . So , by using section formula , the co-ordinates of P =

$(x , y) = (\frac{x^2 + x^1}{2} ,\frac{y^2 + y^1}{2} )$

PROCEDURE :-

Let the co-ordinates of another endpoint be (x , y)

So ,

$(-8 , -4) = (\frac{-4 + x}{2} , \frac{-10 + y}{2} )$

First , lets solve for x.

$=> \frac{x - 4}{2} = -8$

$=> x - 4 = -8 \times 2 = -16$

$=> x = -16 + 4 = -12$

Now , lets solve for y.

$=> \frac{y - 10}{2} = -4$

$=> y - 10 = -4 \times 2 = -8$

$=> y = -8 + 10 = 2$

∴ The co-ordinates of another endpoint = (-12 , 2)

3 0

3 years ago

6. Calculate the area of the octagon in the figure below.

Kryger [21]

Answer:

$41\text{ [units squared]}$

Step-by-step explanation:

The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.

The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:

4 triangles (corners)
3 rectangles (one in the middle, two on top after you remove triangles)

Formulas:

Area of rectangle with length $l$ and width $w$ : $A=lw$
Area of triangle with base $b$ and height $h$ : $A=\frac{1}{2}bh$

Area of triangles:

All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.

Thus, the total area of one is $A=\frac{1}{2}\cdot 2\cdot 2=2\text{ square units}$

The area of all four is then $2\cdot 4=8$ units squared.

Area of rectangles:

The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of $3\cdot 2=6$ units squared, and the both of them have a total area of $6\cdot 2=12$ units squared.