<h2>distance = 523 cm</h2>
Explanation:
( a ) The rotational speed of the ladybug = 25 r.p.m = 25/60 r.p.s
= 5/12 rev/sec
( b ) The definition of frequency is the number of rotations per second .
Here the number of rotations per second is 5/12 . Thus frequency = 5/12 Hz
( c ) The tangential speed is v = angular velocity x radius of rotation
The angular velocity ω = 2π x n , where n is the number of rotations per second
Thus angular velocity = 2π x 5/12 = 5π/6 rad/sec
The linear velocity = angular velocity x distance from center of record
Thus tangential speed = 5π/6 x 10 = 25π/3 cm/sec
Angular displacement in 20 sec = ω x t = 5π/6 x 20 = 50π/3 rad
Linear displacement = angular displacement x distance from center of record
= 50π/3 x 10 = 500π/3 = 523 cm
Answer:
C.) To indicate different versions of the same variable.
Explanation:
Variables in physics often include a subscript. These subscripts are used for indicating different versions of the same variable in physics.
Basically, subscripts are used to represent the beginning (initial) and ending (final) position or point of a variable in physics.
For example, we would look at Gay Lussac' Law of gases.
Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Gay Lussac's law is given by;
Where;
represents the initial temperature.
represents the initial temperature.
represents the initial pressure.
represents the initial pressure.
Note: 1 and 2 are the subscript while T and P are the variables.
W=F*D
83J=F*14
83/14=F
5.92N
Answer:
A. 2.8 m/s
Explanation:
Suppose that at the height of 0 m, the path of the pendulum is lowest.
If we use law of conservation of energy, the pendulum will have zero kinetic energy or K.E when it is at highest point, because K.E happens during movement of object and at the highest point all the energy will be P.E
P.E= mgh
Similarly, when the pendulum reaches at the lowest point, the height becomes zero and the P.E also becomes zero. Now all the energy will be K.E
K.E= 1/2 m v^2
In question, we are asked about the speed as the pendulum it reaches the lowest point of its path. Like we mentioned P.E will be zero at lowest point because of zero height. And also we will use law of conservation of energy because no energy has been lost from system.
K.E= P.E
1/2 m v^2 = mgh
Taking sq.root at both sides
v= Under root 2 gh
v=Under root 2x 9.8 m/s x0.4 m
v=Under root 7.84
v=2.8 m/sec
Hope it helps!
