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3 years ago

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An astronaut measures her mass by means of a device consisting of a chair attached to a large spring.Her mass can be determined

from the period of the oscillations she undergoes when set into motion.If her mass together with the chair is 170 kg, and the spring constant is 1250 N/m, what time is required for her to undergo 10 full oscillations?

1 answer:

Olenka [21]3 years ago

6 0

Answer:

23 seconds

Explanation:

Step one:

given data

mass m= 170kg

The spring constant is 1250 N/m

Required

The period required for 10 oscillations

Step two:

The expression relating period, mass, and spring constant is

$T=2 \pi \sqrt{\frac{m}{k} } \\$

substituting our data we have

$T=2 *3.142 \sqrt{\frac{170}{1250} } \\\\T=6.284* \sqrt{0.136}\\\\T=6.284*0.3687\\T=2.3s$

A Period is defined as the time required to complete one full oscillation

hence, having found the period to be 2.3 seconds, the time required for 10 oscillations will be 2.3*10= 23seconds

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