How does visible light interact with objects to produce the colors we see?

Physics

1 answer:

Kipish [7]3 years ago

3 0

Answer:

Visible light when all put together is white. When objects appear to be, lets say, red, it would be the only color not absorbed by that object. same goes with all other colors. So black objects absorb all colors (not 100%) and that is why black clothing gets hotter, it simply absorbs all incoming light, as apposed to white that will reflect the colors back, making all of them together appear white. Hope this helps, not the best at explaining things.

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In which situation is work not being done?

almond37 [142]

work done =W = F.d = F d cosФ (Ф is angle between force F and displacement d) If a body/object is moving on a smooth surface (friction-less surface ) .There is no force acting on that body. F=0 so W=FdcosФ= (0)dcosФ ⇒ W=0

Now if a body is facing some amount of force but under the action of force there is no displacement covered. d=0 so W =FdcosФ= F(0)cosФ ⇒W=0

example: A person is applying a force on rigid wall but wall remains at rest there is no displacement occurs in wall.

The third term upon which work done dependent is angle between force and displacement i.e Ф. If Ф=90° then W= FdcosФ= Fdcos90⇒ W=0 ( as cos 90°=0)