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kicyunya [14]
3 years ago
15

Who is drinking the fastest

Mathematics
1 answer:
AleksandrR [38]3 years ago
3 0

Answer: Caiden

Step-by-step explanation:

For Caiden, at the second minute, the water is already at 7 ounces. However, Bella is still at 8 ounces. And Caiden is drinking at a speed of 2.5 ounces per minute while Bella is drinking at a speed of 2 ounces per minute.

Hope that helped!

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The answer is 0.00008325

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Given a = -3,b= 4 and e=-5, evaluate a+b+c
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-4

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toby used 4 inches of tape to wrap a gift how much tape will he need to wrap 5 more of the same gift?
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3 years ago
What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 2x + y - 1=0?​
elixir [45]

Answer:

y=-2x+4

Step-by-step explanation:

2x+y-1=0

2x+y=0+1

2x+y=1

y=1-2x

y=-2x+1

y=mx+b where m=slope and b=y-intercept

parallel means same slope,

so the slope would still be -2.

--------------

y-y1=m(x-x1)

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7 0
3 years ago
Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes
Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2\times 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 \times 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled \triangle AOB.

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = \dfrac{Total\ distance}{Total\ time}

\Rightarrow \dfrac{74.28}{5} = 14.86\ knots

6 0
3 years ago
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