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JulsSmile [24]
4 years ago
14

An (blank) is an abbreviation for the name of an element and usualy has eighter one or two letters

Chemistry
1 answer:
nata0808 [166]4 years ago
5 0
The <span>Chemical Symbol is the Abbreviation for the name of an element.</span>
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Figuring out how to make a better type of plastic is which type of research
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Answer:applied chemistry

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How can Newton's Third Law of Motion be used to explain why it is difficult to walk on a slippery surface, such as ice?
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E ground pushes you forward. But that interaction is friction. Reduce friction and it doesn't matter how strong your legs are, the surface is incapable of pushing you accordingly. The coefficient of static friction is very low so it is easy to slide your foot rather than push.
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3 years ago
The osmotic pressure of a solution formed by dissolving 75.0 mg of aspirin (c9h8o4) in 0.250 l of water at 25 °c is ________ atm
Igoryamba

Answer is: the osmotic pressure of aqueous solution of aspirin is 0.0407 atm.

m(C₉H₈O₄) = 75 mg ÷ 1000 mg/g = 0.075 g.

n(C₉H₈O₄) = 0.075 g ÷ 180.16 g/mol.

n(C₉H₈O₄) = 0.000416 mol.

c(C₉H₈O₄) = 0.000416 mol ÷ 0.250 L.

c(C₉H₈O₄) = 0.00167 M; concentration of solution.

T(C₉H₈O₄) = 25°C = 298.15 K; temperature in Kelvins.

R = 0.08206 L•atm/mol•K; universal gas constant.

π = c(C₉H₈O₄) • T(C₉H₈O₄) • R.

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3 0
3 years ago
A reactant decomposes with a half-life of 29.5 s when its initial concentration is 0.229 M. When the initial concentration is 0.
Dmitrij [34]

Answer :

The order of reaction is, 0 (zero order reaction).

The value of rate constant is, 0.00388Ms^{-1}

Explanation :

Half life : It is defined as the time in which the concentration of a reactant is reduced to half of its original value.

The general expression of half-life for nth order is:

t_{1/2}\propto \frac{1}{[A_o]^{n-1}}

or,

\frac{t_{1/2}_1}{t_{1/2}_2}=\frac{[A_2]^{n-1}}{[A_1]^{n-1}}

or,

n=\left(\frac{\log\frac{(t_{1/2})_1}{(t_{1/2})_2}}{\log\frac{(A)_2}{(A)_1}}\right )+1           .............(1)

where,

t_{1/2} = half-life of the reaction

n = order of reaction

[A] = concentration

As we are given:

Initial concentration of A = 0.229 M

Final concentration of A = 0.639 M

Initial half-life of the reaction = 29.5 s

Final half-life of the reaction = 82.3 s

Now put all the given values in the above formula 1, we get:

n=\left (\frac{\log \frac{29.5}{82.3}}{\log\frac{0.639}{0.229}}\right )+1

n=0.000196\approx 0

Thus, the order of reaction is, 0 (zero order reaction).

Now we have to determine the rate constant.

To calculate the rate constant for zero order the expression will be:

t_{1/2}=\frac{[A_o]}{2k}

When,

t_{1/2} = 29.5 s

[A_o] = 0.229 M

29.5s=\frac{0.229M}{2k}

k=0.00388Ms^{-1}

Thus, the value of rate constant is, 0.00388Ms^{-1}

4 0
3 years ago
Is holding an ice cube on your hand a chemical change?
Strike441 [17]
Yes. its a chemichal change.
7 0
3 years ago
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