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Elanso [62]
3 years ago
15

An infrared light detector would be most beneficial to someone who investigates

Chemistry
2 answers:
Marat540 [252]3 years ago
8 0

Answer:

a

Explanation:

because it works for radiations

aliya0001 [1]3 years ago
5 0
A
Because it works for radiations
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In a chromatography experiment, chlorophyll pigments are separated using paper. What is the stationary phase in this experiment?
Bond [772]
Answer:
The stationary phase in chromatography experiment is paper.

Explanation:
In chromatography experiment, the stationary phase is defined as the fixed substance that is necessary to start chromatography. In our case, this fixed substance is paper, so that makes paper our stationary phase.

Hope this helps :)
4 0
3 years ago
Read 2 more answers
10. Write the formula for the compounds: copper (1) chloride and copper (II) chloride
Natali [406]

Answer:

Copper(II) chloride (CuCl2) reacts with several metals to produce copper metal or copper(I) chloride (CuCl) with oxidation of the other metal.

Explanation:

3 0
3 years ago
Cuando aumenta la temperatura dentro de un recipiente cerrado que contiene un gas este se expande/comprime por que las partícula
Evgesh-ka [11]

Answer:

expande

forman se alejan

Explanation:

Según las leyes de los gases ideales;

La ley de Charles establece que el volumen de una masa dada de gas ideal es directamente proporcional a su temperatura a la presión simultánea.

Esto significa que cuando se calienta una masa dada de gas ideal, el gas se expande y las moléculas de gas se alejan unas de otras de acuerdo con la ley de Charles.

7 0
3 years ago
Which of the following pairs of aqueous solutions produce a precipitate?
dolphi86 [110]

Answer:

NaCi + LiCl is the correct answer

6 0
3 years ago
Let a represent the red spheres and b represent the blue spheres. write a balanced equation for the equilibrium reaction.
krok68 [10]
I have attached the diagram related to this question.

Answer:
5A₂ + 5B .................> 4A₂B + A₂ + B

Explanation:
1- For the reactants:
We can note that:
i- we have 5 moles of substance A which is diatomic. This means that we have 5A₂
ii- we have 5 moles of substance B which is monoatomic. This means that we have 5B
Based on the above, for the reactants side, we have:
5A₂ + 5B

2- For the products:
We can note that:
i- we have 4 moles of a substance formed from the combination of two moles of substance A with one mole of substance B. This means that we have 4A₂B
ii- we have one mole of substance A that is diatomic. This means that we have A₂
iii- we have one mole of substance B that is monoatomic. This means that we have B
Based on the above, for the products side, we have:
4A₂B + A₂ + B

3- Combining reactants and products parts:
Combining the reactants side (from part 1) with the products side (from part 2), we can find that the initial equation is as follows:
5A₂ + 5B .................> 4A₂B + A₂ + B

4- Balancing the equation:
Taking a look at the initial equation we reached in part 3, we will find that:
Number of moles of substance A in reactants = 2*5 = 10 moles
Number of moles of substance A in products = 2*4 + 2*! = 10 moles
SUBSTANCE A IS BALANCED
Number of moles of substance B in reactants = 5*1 = 5 moles
Number of moles of substance B in products = 4*1 + 1 = 5 moles
SUBSTANCE B IS BALANCED
Based on the above, the final balanced equation is the same as the initial equation reached in part 3:
5A₂ + 5B .................> 4A₂B + A₂ + B

Hope this helps :)

6 0
3 years ago
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