Explanation:
According to the Henderson-Hasselbalch equation, the relation between pH and 
is as follows.
pH = 
where, pH = 7.4 and = 7.21
As here, we can use the nearest to the desired pH.
So, 7.4 = 7.21 + 
0.19 =
= 1.55
1 mM phosphate buffer means ![[HPO_{4}]](https://tex.z-dn.net/?f=%5BHPO_%7B4%7D%5D)
+ ![[H_{2}PO_{4}]](https://tex.z-dn.net/?f=%5BH_%7B2%7DPO_%7B4%7D%5D)
= 1 mM
Therefore, the two equations will be as follows.
= 1.55 ............. (1)
+ = 1 mM ........... (2)
Now, putting the value of from equation (1) into equation (2) as follows.
1.55![[H_{2}PO_{4}] + [tex][H_{2}PO_{4}]](https://tex.z-dn.net/?f=%5BH_%7B2%7DPO_%7B4%7D%5D%20%2B%20%5Btex%5D%5BH_%7B2%7DPO_%7B4%7D%5D)
= 1 mM
2.55 = 1 mM
= 0.392 mM
Putting the value of in equation (1) we get the following.
0.392 mM + = 1 mM
= (1 - 0.392) mM
= 0.608 mM
Thus, we can conclude that concentration of the acid must be 0.608 mM.
The correct answer among all the other choice is B. molecule. The molecule is the smallest particle of water. All the other options are wrong. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.
We can see from the details below that, the value of the solution's molality is 1.14 mol/Kg.
<h3>What is solubility?</h3>
The term solubility has to do with the quantity of solute that is able to dissolve in a given quantity of solvent. We have the solubility of the sodium hydrogen carbonate in water at 20 degrees as 9.6 g/100 g h2o.
Number of moles of sodium hydrogen carbonate = 9.6 g/84 g/mol = 0.114 moles
Number of moles water = 100 g /18 g/mol = 5.55 moles
Mole fraction of sodium hydrogen carbonate is obtainable by the use of the relation;
0.114 moles/0.114 moles + 5.55 moles
= 0.02
Molality of the solution = 0.114 moles/0.1 Kg = 1.14 mol/Kg
Learn more about solubility:brainly.com/question/8591226
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Answer:
The binding energy released is 1.992 X 10⁻¹⁸ J
Explanation:
Given;
mass of the alpha particle, m = 6.64 x 10⁻²⁷ kg
speed of the alpha particle, c = 3 x 10⁸ m/s
The binding energy released is given by;
where;
m is mass of the particle
c is speed of the particle
E = 6.64 x 10⁻²⁷ (3 x 10⁸)²
E = 1.992 X 10⁻¹⁸ J
Therefore, the binding energy released is 1.992 X 10⁻¹⁸ J
Explanation:
Large hydrocarbon molecules can be cracked in an oil refinery through the process of cracking. Cracking of hydrocarbons involves the use of heat, pressure and catalyst to resolve heavy hydrocarbons into simpler and more useful products.
- Cracking of hydrocarbons is very essential in the oil refinery.
- Cracking helps to break giant hydrocarbon molecules into simple and more useful ones.
- Fractional distillation separates oil molecules into its different components based on their different boiling points.
- The fractions produced a times are usually long chained and are not in high demand.
- Catalytic cracking and thermal cracking helps to break the long chains of the heavy hydrocarbons fractions into simpler ones.
Learn more:
conversions brainly.com/question/4586309
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