"<span>How much did your classmates typically spend on music downloads last year?" is a statistical question, and the units would </span>be both the number of students and how many downloads each individual bought.
What are you trying to do here?
Solve the graph, or make it appear as something else?
First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0
sec (x) (2sec (x) -2) = 0
Then we're going to separate the two to find the zeros of each because anything time 0 is zero.
sec(x) = 0
2sec (x) - 2 = 0
Now, let's simplify the second one as the first one is already.
Add 2 to both sides:
2sec (x) = 2
Divide by 3 on both sides:
sec (x) = 1
I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
We can find the side length of square 3 by dividing by 4, which is 9.
Then, we find the side length of square 2 by dividing it by 4, which is 12.
To find the AREA of square 1, we do a^2+b^2=c^2. This is basically adding up area of square 1 and square 2 to get square 3.
a^2+b^2=c^2
9^2+12^2=c^2
81+144=225
So the area is 225 units.
Answer:
The minutes wouldn't it be hours?
Step-by-step explanation:
I hope this helps you
6740/10=674
6740/3=2,246666
