Company C services 16 office suites.
Company A services 1/3 of the suites and Company B services 2/5; together they service 1/3+2/5. Find a common denominator; 15 is the smallest:
1/3=5/15
2/5=6/15
5/15+6/15 = 11/15
This means that 1-11/15 = 4/15 of the suites are serviced by Company C.
4/15 of 60 = 4/15(60) = 4/15(60/1) = 240/15 = 16
Answer:
required probability is .3446
Step-by-step explanation:
It is given that most expected time of completion = 90 days
Variance = 25
We know that

Thus the standard normal deviate is given by

Applying values we get

Using the standard table for Z we have probability corresponding to Z = -0.4 equals 0.3446
Thus required probability is .3446
Answer:
if you solve it for the t your answer would be: pt+30pte−0.2t=600
but if you solved it for the p your answer would be: p=600t(1+30e−0.2t)
hope it works, sweete
Answer:

that should give you the answer but it's really blurry so I cant see it