Answer:
I believe the answer is 20 and 30
Answer:
We have to prove
sin(α+β)-sin(α-β)=2 cos α sin β
We will take the left hand side to prove it equal to right hand side
So,
=sin(α+β)-sin(α-β) Eqn 1
We will use the following identities:
sin(α+β)=sin α cos β+cos α sin β
and
sin(α-β)=sin α cos β-cos α sin β
Putting the identities in eqn 1
=sin(α+β)-sin(α-β)
=[ sin α cos β+cos α sin β ]-[sin α cos β-cos α sin β ]
=sin α cos β+cos α sin β- sinα cos β+cos α sin β
sinα cosβ will be cancelled.
=cos α sin β+ cos α sin β
=2 cos α sin β
Hence,
sin(α+β)-sin(α-β)=2 cos α sin β
Answer:
x=13
Step-by-step explanation:
We add all the numbers together, and all the variables
6x-78
We move all terms containing x to the left, and all other terms to the right
6x=78
x=78/6
which should equal 13
The perimeter would be about 34.4 because if you choose the bottom side to be ten, by multiplying 35 by 2 to get 70 you can divide by 10 to get 7. Since you know the height and width, you can use pythagorean theorem, a^2 + b^2 = c^2. Plug in the numbers you have 10^2+7^2=c^2. c^2=149, so if you square root 149 you will get a irrational number but when rounded you get 12.2- so that is one side multiply by 2 and get 24.4- and add 10 to get 34.4
