Answer:
mean = 1 power failure
variance = 1 (power failure)²
Step-by-step explanation:
Since the mean is computed as
mean = E(x) = ∑ x * p(x) for all x
then for the random variable x=power failures , we have
mean = ∑ x * p(x) = 0 * 0.4 + 1* 0.3 + 2*0.2 + 3* 0.1 = 1 power failure
since the variance can be calculated through
variance = ∑[x-E(x)]² * p(x) for all x
but easily in this way
variance = E(x²) - [E(x)]² , then
E(x²) = ∑ x² * p(x) = 0² * 0.4 + 1²* 0.3 + 2²*0.2 + 3²* 0.1 = 2 power failure²
then
variance = 2 power failure² - (1 power failure)² = 1 power failure²
therefore
mean = 1 power failure
variance = 1 power failure²
Answer:

Step-by-step explanation:
we know that
If triangles EFG and QRS are similar
then
the scale factor is equal to the measure of the smallest side of triangle QRS divided by the smallest side of triangle EFG
so
Let
x-------> the smallest side of triangle QRS
y-------> the smallest side of triangle EFG
z-------> the scale factor
we have

substitute the values


Find the length of the longest side of QRS
The length of the longest side of QRS is equal to multiply the scale factor by the length of the longest side of EFG
so

Answer:
A) 35
B) 22
Step-by-step explanation:
A) just count how many numbers there are after the bar
B) don't count the 14.0s only the 14.2 and aboves
Answe70
Step-by-step explanation:
Answer:
y=4
Step-by-step explanation:
You can ignore the 3 and 6 because this has no y value change(rise over run)
This is a straight horizontal line so the equation is y=4.
Slope=0