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vesna_86 [32]
3 years ago
8

Need with these thank you if you help

Mathematics
1 answer:
Aleks [24]3 years ago
3 0
A. p^4/p^7 = p^-3 = 1/p^3
b. 4^3/4^3 = 1
c. 11^2/11^4 = 11^-2 = 1/11^2
d. 6^4/6 = 6^3
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Find the product of (2x − 5y)2
pishuonlain [190]

Answer:

(2x - 5y)²

(2x - 5y)(2x - 5y)

2x(2x - 5y) - 5y(2x - 5y)

2x(2x) - 2x(5y) - 5y(2x) + 5y(5y)

4x² - 10xy - 10xy + 25y²

4x² - 20y + 25y²

The answer is B.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
What is the equation in point slope form of the line that passes through the point (2,6) and has slope of 5?
sleet_krkn [62]
Firstly, you can use the slope and the first point to find a second point:
2 + 1 = x2 and 6 + 5 = y2 because the slope is 5/1. 
Next you can write the equation in point-slope form (remember point-slope form is y - y1 = m(x - x1):
y - 11 = 5(x - 3) 
Another equation would be B because B is the correct equation if you choose 2 as x2 and 6 as y2. 
Hope this helps!

5 0
3 years ago
Read 2 more answers
How can you tell that the data in the table is function or not?
stealth61 [152]

that is not a function, because there are two outputs for three. two inputs can have one output, but one input cant have two outputs.

6 0
3 years ago
I need help with this and fast if possible
11Alexandr11 [23.1K]

Answer:

<em>The answer is Hence Proved</em>

Step-by-step explanation:

       Given that CB║ED ,  CB ≅ ED

       To prove Δ CBF ≅ Δ EDF

  •       CB ≅ ED   ( Given )

        This means that the length of CB is equal to ED

        As CB║ED The following conditions satisfies when a transversal cut

        two parallel lines

  •    ∠ EDF = ∠ FBC   ( Alternate interior points )
  •    ∠ DEF = ∠ FCB   ( Alternate interior points )

       ∴ Δ CBF ≅ Δ EDF    ( By ASA criterion)

        The Δ CBF is congruent to Δ EDF By ASA criterion .

    <em>    Hence proved </em>

6 0
3 years ago
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