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vesna_86 [32]
3 years ago
8

Need with these thank you if you help

Mathematics
1 answer:
Aleks [24]3 years ago
3 0
A. p^4/p^7 = p^-3 = 1/p^3
b. 4^3/4^3 = 1
c. 11^2/11^4 = 11^-2 = 1/11^2
d. 6^4/6 = 6^3
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If you divided 20acres of land into 1\4 acre section how !any sections doses it divied to
LuckyWell [14K]
If you divide 20 acres into 1/4 sections you'll get
20 ÷ 1/4 sections. When you divide fractions, you just multiply the reciprocal.

20 ÷ 1/4 =
20 × 4/1 = 80 sections
5 0
3 years ago
If p is a positive integer, and 4 is the remainder when p-8 is divided by 5, which of the following
malfutka [58]
<h2>sorry I can't help you to solve the equation</h2>
6 0
2 years ago
An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh
natima [27]

Answer:

Speed of the plane in still air: 779\; {\rm km \cdot h^{-1}}.

Windspeed: 100\; {\rm km \cdot h^{-1}}.

Step-by-step explanation:

Assume that x\; {\rm km \cdot h^{-1}} is the speed of the plane in still air, and that y\; {\rm km \cdot h^{-1}} is the speed of the wind.

  • When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be (x - y)\; {\rm km \cdot h^{-1}}.
  • When this plane is travelling in the same direction as the wind, the ground speed of this plane would be (x + y)\; {\rm km \cdot h^{-1}}.

The question states that when going against the wind (v = (x - y)\; {\rm km \cdot h^{-1}},) the plane travels 6111\; {\rm km} in 9\; {\rm h}. Hence, 9\, (x - y) = 6111.

Similarly, since the plane travels 7911\; {\rm km} in 9\; {\rm h} when travelling in the same direction as the wind (v = (x + y)\; {\rm km \cdot h^{-1}},) 9\, (x + y) = 7911.

Add the two equations to eliminate y. Subtract the second equation from the first to eliminate x. Solve this system of equations for x and y: x = 779 and y = 100.

Hence, the speed of this plane in still air would be 779\; {\rm km \cdot h^{-1}}, whereas the speed of the wind would be 100\; {\rm km \cdot h^{-1}}.

3 0
1 year ago
The airplane in the scale drawing has a wingspan of a feet and a tail span of b feet. If the tailspin in the drawing is 2 inches
xeze [42]

Correct answer is: actual wingspan of airplane is 6 inches.

Solution:-

We are given that wingspan is 'a' feet and tail span is 'b' feet in a scale drawing.

And we are also given that tail span is 2 inches that is b=2 inches and \frac{a}{b}=3

Let us plugin the b value in above equation.

\frac{a}{2}=3

Multiplying with 2 on both sides.

a=3X2=6 inches.

Hence actual wingspan of airplane is 6 inches.

7 0
3 years ago
Solve the equation:<br><br> 3t²-3t+1=0
podryga [215]

Answer:

There are no solutions

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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