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3 years ago

8

Need with these thank you if you help

1 answer:

Aleks [24]3 years ago

3 0

A. p^4/p^7 = p^-3 = 1/p^3
b. 4^3/4^3 = 1
c. 11^2/11^4 = 11^-2 = 1/11^2
d. 6^4/6 = 6^3

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An angle measured 10 degrees less than the measure of its complementary angle. Find the measure of both angles

Mazyrski [523]

Answer:

The measure of the angles are 40 degrees and 50 degrees

Step-by-step explanation:

Let

x ----> the measure of one angle in degrees

y ----> the measure of the complementary angle in degrees

we know that

If two angles are complementary, then their sum is equal to 90 degrees

so

$x+y=90$ ----> equation A

we have that

$x=y-10$ ----> equation B

Substitute equation B in equation A and solve for y

$(y-10)+y=90\\2y-10=90\\2y=100\\y=50$

Find the value of x

$x=50-10=40$

therefore

The measure of the angles are 40 degrees and 50 degrees

3 0

3 years ago

When you ___ , ___ or ____ polynomials, they are ____ which means the exponents are positive whole numbers

tresset_1 [31]

Answer:

Step-by-step explanation:

8 0

3 years ago

Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

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3 years ago

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Tpy6a [65]

You could try and multiply I believe so .

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2 years ago

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A pattern has 38 black squares to every 24 red squares. What is the ratio of black squares to red squares?

Nostrana [21]

Answer:

Step-by-step explanation:

38/24=19/12

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2 years ago

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