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3 years ago

Look at this graph: y : Is this relation a function? yes no Submit

Mathematics

1 answer:

iren [92.7K]3 years ago

3 0

Answer:

Yes

Step-by-step explanation:

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3 years ago

I need help understanding rate of change and slope.

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3 years ago

Read 2 more answers

-4(2 - 4n) -5(3n +6)

balandron [24]

I hope this helps :))))

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3 years ago

Can you help me please, please answer seriously, no links please

Talja [164]

Answer:

Centre: $(\frac{1}{2} ,2)$

Radius = $2$

Step-by-step explanation:

General formula for a circle: $(x-a)^2+(y-b)^2=r^2$ , where $r=$ the radius of the circle and $(a,b)$ is the centre of the circle.

To find the centre and radius of the circle we should re-write the given equation in the form of the general formula.

So, put the terms with the same variables together:

$4x^2-4x+4y^2+16y+1=0$

We can see that there is a common factor of $4$ , so let's simplify by dividing by $4$ :

$x^2-x+y^2+4y+\frac{1}{4} =0$

Here we can get it into the general formula by completing the square.

We do this by turning a quadratic with form $ax^2+bx+c=0$ into the form $(x-d)^2-e+c=0$ , where d is half of the coefficient of $x$ , e is $d^2$ and c is the constant of the quadratic.