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photoshop1234 [79]

3 years ago

11

Are anybody good at Math that could help me with all these answers and get them right and show your work and If you do it you ge

t 27 points.

1 answer:

zepelin [54]3 years ago

3 0

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Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.

Keith_Richards [23]

Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

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3 years ago

B/11-6b/11=10/11 solve for b asap

Mrac [35]

I hope this helps you

b-6b/11=10/11

-5b=10 (divide -5 both of sides)

b=-2

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3 years ago

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Daniel [21]

Check the attachment for answer.

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4 years ago

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If the ration of bananas to apples was 9 to 15. If there were twelve bananas, how many total pieces of fruits was there

KiRa [710]

Answer:

IM not too sure but i think 30

Step-by-step explanation:

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3 years ago

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A circle is inscribed in a square with a side length of 144. If a point in the square is chosen at random, what is the probabili

____ [38]

Given :

A circle is inscribed in a square with a side length of 144.

So, radius of circle, r = 144/2 = 72 units.

To Find :

The probability that the point is inside the circle.

Solution :

Area of circle,

$A_c = \pi r^2\\\\A_c = 3.14 \times 72^2\ units^2\\\\A_c = 16277.76 \ units^2$

Area of square,

$A_s = (2r)^2\\\\A_s = ( 2 \times 72)^2\ units^2\\\\A_s = 20736\ units^2$

Now, probability is given by :

$P = \dfrac{A_c}{A_s}\\\\P = \dfrac{16277.76}{20736}\\\\P = 0.785$

Therefore, the probability that the point is inside the circle is 0.785 .

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3 years ago