840 is the answer
i hope i helped!
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
k = 3
Step-by-step explanation:
Given that y and x are directly related then the equation relating them is
y = kx ← k is the constant of variation
To find k use the condition y = 81 when x = 27
k =
=
= 3
I saw the figure of the fishpond. It composed of a rectangle and a circle. The circle is cut into two and each half is attached to the width of the rectangle making an oblong shaped fishpond.
Length of the rectangle: 2.5 inch
Width of the rectangle and diameter of the circle: 1 inch
1/2 inch equals 15 feet.
2.5 inches = 75 feet
1 inch = 30 feet
Area of a rectangle = 75 ft * 30 ft = 2,250 ft²
Area of a circle = 3.14 * (15ft)² = 3.14 * 225ft² = 706.50 ft²
Total Area = 2,250 ft² + 706.50 ft² = 2,956.50 ft²
The first and last one are true!