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2 years ago

Scott is four more than double the age of Todd. Scott is 56. What is Todd's age?

Mathematics

1 answer:

SSSSS [86.1K]2 years ago

5 0

Answer: 26 years old

Step-by-step explanation:

Since Scott is four more than double the age of Todd, start by taking away four from Scott's age.

56-4=52

Then take half of that because that would be double of Todd's age

52/2=26

Todd is 26 years old.

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Need help please its my last question

Nesterboy [21]

Given:

Radius of circle = 12 units

Area of sector = 24π sq. units.

Central angle = x

To find:

The value of x.

Solution:

We have,

$r=12$

$A=24\pi$

$\theta = x$

We know that, area of a sector is

$A=\dfrac{\theta }{360^\circ}\pi r^2$

Where, $\theta$ is central angle, r is radius.

$24\pi=\dfrac{x}{360^\circ}\pi (12)^2$

$24\pi=\dfrac{x}{360^\circ}\pi (144)$

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3 years ago

15 20 Need to reduce this fraction to the lowest terms

wlad13 [49]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

4. Write an equation for the line that is parallel to the given line and that passes

pentagon [3]

Answer:

$y=\frac{5}{2}x-14$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)
Parallel lines always have the same slope

1) Determine the slope (m)

$y=\frac{5}{2}x-10$

In the given equation, $\frac{5}{2}$ is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of $\frac{5}{2}$ . Plug this into $y=mx+b$ :

$y=\frac{5}{2}x+b$

2) Determine the y-intercept (b)

$y=\frac{5}{2}x+b$

Plug in the given point (-6,-29) and solve for b

$-29=\frac{5}{2}(-6)+b$

Simplify -6 and 2

$-29=\frac{5}{1}(-3)+b\\-29=(5)}(-3)+b\\-29=-15+b$

Add 15 to both sides to isolate b

$-29+15=-15+b+15\\-14=b$

Therefore, the y-intercept is -14. Plug this back into $y=\frac{5}{2}x+b$ :

$y=\frac{5}{2}x-14$

I hope this helps!

4 0

2 years ago

Solve by completing the square x squared +14x - 51=0

Nesterboy [21]

$x^2 +14x - 51=0\\ \\\Delta = b^{2}-4ac =14^{2}-4*1*(-51)=196+204=400 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-14- \sqrt{400}}{2}=\frac{-14-20}{2}= \frac{-34}{2}=-17\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-14+ \sqrt{400}}{2}=\frac{-14+20}{2}= \frac{6}{2}=3$

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3 years ago