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3 years ago

13

Anthony bought an 8 foot board. He cut off 3/4 of the board to build a shelf and gave 1/3 of the rest to his brother for an art

project. How many inches long was the puece Antjony gave to his brother?

1 answer:

jolli1 [7]3 years ago

7 0

Anthony gave 0.75 or75 inches to his brother

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What is the value of d when 11(d+1)=4(d+8)

andreev551 [17]

The answer is D=3 11(3*+1)=4(3*+8)
11(4)=4(11)
44=44

4 0

3 years ago

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If a sequence of 8 consecutive odd integers with increasing values has 9 as its seventh term. What is the sum of the terms of th

klemol [59]

Answer:

$Sum = 32$

Step-by-step explanation:

Given

Sequence = Consecutive Odds

$T_7 = 9$

Required

The sum of the terms

A sequence of odd number has a difference of 2. So, the sequence is represented as:

$S = \{-3,-1,1,3,5,7,9,11\}$

Add up all terms in the sequence

$Sum = -3-1+1+3+5+7+9+11$

$Sum = 32$

8 0

3 years ago

Two paper drink cups are shaped like cones. The small cone can hold 6 oz of water. The large cone is 4/3 the height and 4/3 the

dolphi86 [110]

The answer you’re looking for is c 4.5 oz

5 0

3 years ago

Please help very urgent

Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

3 years ago

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16. What is the area of the shaded region in terms of Tr? [20 points]

tangare [24]

Area of the circle outside
= πr2
= π(5)2
=25 π

Area of the bigger circle inside
= π x(3)2
= 9 π
Area of the smaller circle inside
= π x (2)2
= 4 π

Area of shaded region
= 25π - 9π - 4π
= 12π square unit

6 0

2 years ago