1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ray Of Light [21]
3 years ago
9

5n+3n=40Pls give me an answer and solution.... ​

Mathematics
2 answers:
nevsk [136]3 years ago
8 0

Answer:

3 times 5 = 15 and 5 times 5 = 25. 15 plus 25 = 40

Step-by-step explanation:

ale4655 [162]3 years ago
3 0
N=5.
move all terms that don’t contain n to the right side and solve
You might be interested in
Find 140 percent of 15.
Setler [38]

Answer:

21

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Lisa is cooking muffins. The recipe calls for 7 cups of sugar. She has already put in 5 cups. How much more cups does she need t
snow_tiger [21]

Answer:

2 cups!

Step-by-step explanation:

6 0
4 years ago
K=am+3mx solve for m
Otrada [13]
Assuming the variables are constants, you isolate m. So move am to the left. K-am=emx. Now divide ex. This gives you, m=(K-am/ex)
7 0
3 years ago
Exam: 05.03 Exponential and Logarithmic Functions Mid-Module Check<br><br><br> Solve 4x = 8x − 1
Fantom [35]
If 4x = 8x - 1 then 4x must be equivalent to 1. So that means x is .25 or 1/4.

Hope this helps!
(I assumed your trying to solve for x, please word the question better next time)
5 0
3 years ago
Read 2 more answers
Find the integration of (1-cos2x)/(1+cos2x)
slega [8]

Given:

The expression is:

\dfrac{1-\cos 2x}{1+\cos 2x}

To find:

The integration of the given expression.

Solution:

We need to find the integration of \dfrac{1-\cos 2x}{1+\cos 2x}.

Let us consider,

I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx

I=\int \dfrac{2\sin^2x}{2\cos^2x}dx         [\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]

I=\int \dfrac{\sin^2x}{\cos^2x}dx

I=\int \tan^2xdx                      \left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]

It can be written as:

I=\int (\sec^2x-1)dx             [\because 1+\tan^2 \theta =\sec^2 \theta]

I=\int \sec^2xdx-\int 1dx

I=\tan x-x+C

Therefore, the integration of \dfrac{1-\cos 2x}{1+\cos 2x} is I=\tan x-x+C.

8 0
3 years ago
Other questions:
  • The product of t and s less than 3
    11·1 answer
  • What expression is equal to 6(-3m) times 4
    5·1 answer
  • What is the quotient when 2x3 + x + 3 is divided by x + 1?
    7·1 answer
  • Help! I don't get this
    11·1 answer
  • Factor 5x2 – 17x – 12
    10·2 answers
  • Fred's Fruit Stand has 252 pounds of fruit and sells 2 7/8 pounds per hour. Gary's grocery Store has 285 pounds of fruit and sel
    10·1 answer
  • Identify the circumference of ⊙W given that A=121y2π ft2.
    5·1 answer
  • Please help!! Im super confused
    12·1 answer
  • Susan invests $Z at the end of each year for seven years at an annual effective interest rate of 5%. The interest credited at th
    7·1 answer
  • Pls help I cant figure it out ;-;
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!