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2 years ago

Use the GCF and the Distributive Property to find the sum.

Mathematics

2 answers:

Paraphin [41]2 years ago

5 0

Answer:70

Step-by-step explanation:

Like 70?

MrMuchimi2 years ago

4 0

Answer:

gcf:15

Step-by-step explanation:

hope hope this helps

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1/3(12-6x)=4-2x I need help pls

Oksi-84 [34.3K]

Answer:

no solution

Step-by-step explanation:

1/3(12-6x)=4-2x

4-1.3x=4-2x

4=4-0.7x

0=0.7x

5 0

3 years ago

What is the simplified expression for 6(2(y+x))?

koban [17]

It should be B I know how to do it

5 0

2 years ago

Read 2 more answers

The area of cross section of a prism is 45cm² and its height is,10cm. Find its volume

mrs_skeptik [129]

Answer:

The Volume of triangular prism

V = 450 cm³

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given The area of cross section of a prism A = 45cm²

and height (h) = 10 cm

The Volume of triangular prism

V = ( Base area X Height )

= 45 X 10

= 450 cm³

The Volume of triangular prism

V = 450 cm³

6 0

3 years ago

Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n

aliya0001 [1]

Answer:

$f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}$

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

We first compute the n-th derivative of $f(x)=\ln(1+2x)$ , note that

$f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\$

Now, if we compute the n-th derivative at 0 we get

$f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!$

and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

3 0

2 years ago

Which explains how to show that x= -8/3 is a root of 9x^2+48x+64= 0 ?

Helen [10]

Step-by-step explanation:

$9 {( - \frac{8}{3}) }^{} {}^{2} + 48( - \frac{8}{3} ) + 64 \\ \\ 9( - \frac{64}{9} ) - \frac{48}{3} + 64 \\ \\ - 64 - 16 + 64 = - 16$

4 0

3 years ago