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sladkih [1.3K]
3 years ago
10

A laser beam from Earth is reflected by a mirror placed on the Moon. If the speed of the beam is 3.00 x 108 m / s and the distan

ce from Earth to the Moon is 3.81 x 108 m, how long in seconds will the laser beam take to return to its starting point?
Physics
1 answer:
Olin [163]3 years ago
3 0

Answer:

1.27seconds

Explanation:

Speed = 324 m/s , Distance = 411.48m

Time = Distance/Speed

Time = 411.48/324 seconds

Time = 1.27seconds ( Ans)

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Nellie pulls on a 10kg wagon with a constant horizontal force of 30N. If there are no other horizontal gorces what is the wagons
kicyunya [14]

Answer:

a=3m/s^2

Explanation:

If we have a net force F acting on a body of mass m it will experiment an acceleration a. Newton's 2nd Law gives us the relation between these quantities: F=ma.

In our case, we want to calculate the acceleration, so we write:

a=\frac{F}{m}

With the values we have we get:

a=\frac{30N}{10Kg}=3m/s^2

3 0
3 years ago
John is a runner.He runs the 100m sprint in 10.6s.What speed did he travel at (in m/s)​
astraxan [27]
ANSWER: 9.4ms a second

EXPLANATION

100/10.6 = 9.4

Brainiest please?

(Hope this helps you. Have a good day.)

5 0
3 years ago
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Four spheres with positive and negative charges hang from strings.
Arada [10]
Be because it’s the answer
5 0
3 years ago
A flat disk, a solid sphere, and a hollow sphere each have the same mass m and radius r. The three objects are arranged so that
Aloiza [94]

Answer:

b)

Explanation:

Rotational inertia of the sphere: \frac{2}{5}mr^2

Rotational inertia of hollow sphere: \frac{2}{3}mr^2

Rotational inertia of flat disk: \frac{1}{2}mr^2

The largest value is 2/3 mr², therefore, hollow sphere's inertia is largest.

7 0
3 years ago
A jet aircraft is traveling at 260 m/s in horizontal flight. The engine takes in air at a rate of 53.3 kg/s and burns fuel at a
IrinaVladis [17]

Answer:

The thrust of the jet engine is 4188.81 N.

Explanation:

Given that,

Speed = 260 m/s

Rate in air= 53.3 kg/s

Rate of fuel = 3.63 kg/s

Relative speed = 317 m/s

We need to calculate the rate of mass change in the rocket

Using formula of rate of mass

\dfrac{dM}{dt}=\dfrac{dM_{a}}{dt}+\dfrac{dM_{f}}{dt}

Put the value into the formula

\dfrac{dM}{dt}=53.3+3.63

\dfrac{dM}{dt}=56.93\ kg/s

We need to calculate the thrust of the jet engine

Using formula of thrust

T=\dfrac{dM}{dt}u-\dfrac{dM_{a}}{dt}v

Put the value into the formula

T=56.93\times317-53.3\times260

T=4188.81\ N

Hence, The thrust of the jet engine is 4188.81 N.

7 0
3 years ago
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