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sergey [27]
3 years ago
6

How much kinetic energy is required to break through?

Physics
1 answer:
Ksju [112]3 years ago
7 0

Explanation:

The natural environment or natural world encompasses all living and non-living things occurring naturally, meaning in this case not artificial. The term is most often applied to the Earth or some parts of Earth

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Calculate the p.e. of a 5 kg mass when it is (i) 3 m, (ii) 6 m, above the ground. (g = 10 N/kg)​
Mashcka [7]

Explanation:

P.E=MGH

(1) P.E=5×10(G)×3

= 150 kg m^/s^ ( ^ =sqaure)

(2) P.E=5×10×6

= 300 kg m^/s^

Hope it helps, just remember the formula u can solve any question regarding gravition of earth (P.E=Mgh)

4 0
3 years ago
Car A with a mass of 725 kilograms is traveling east at an initial velocity of 15 meters/second. It collides head–on with car B,
ikadub [295]

Answer:

p_t_o_t_a_l=250kg\frac{m}{s}

Explanation:

<u>The total momentum of a system is defined by:</u>

(mv)_t_o_t=m_1v_1+m_2v_2+...

Where,

(mv)_t_o_t is the total momentum or it could be expressed also as p_t_o_t_a_l.

m_1 and m_2 represents the masses of the objects interacting in the system.

v_1 and v_2 are the velocities of the objects of the system.

<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>

We have:

m_1=725 kg

v_1=15\frac{m}{s}\\m_2=625 kg

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.

v_2=-17\frac{m}{s}

Then the total momentum of the system is:

p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}

8 0
4 years ago
What is the name of the device that measures wind speed?
myrzilka [38]
The device is an anemometer<span> 
It's like 4 cups that measure the speed instead of direction

</span>
8 0
4 years ago
Read 2 more answers
Which statement is a hypothesis?
olga_2 [115]
B, do earthworms prefer bright light or darkness!
3 0
2 years ago
Read 2 more answers
Moving by short leaps on one foot at a time.
Evgen [1.6K]

The answer is:

Hopping.

Explanation:

Hopping is done by taking off on one foot and landing back on that same foot. Hopping is done in shorter intervals, meaning you usually don't travel large distances through a single hop. Hopping is categorized as short leaps for its small distance covered singularly, and each hop is done only on one foot.

<em>(Think about if one of your feet/legs is injured or asleep. If you wanted to go from say the living room to the kitchen, but didn't wish to move that leg or foot, you would likely hop on one foot to get to the destination.)</em>

6 0
3 years ago
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