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lidiya [134]
3 years ago
8

What does Atomic Collisions mean

Physics
1 answer:
stiks02 [169]3 years ago
4 0

Answer:

Atomic and molecular collision processes are the physical interactions of atoms and molecules when they are brought into close contact with each other and with electrons, protons, neutrons or ions. This includes energy-conserving elastic scattering and inelastic scattering.

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If 6000 J of heat is added to 200 gm of water at 25° C. What will be its final<br>temperature?​
Debora [2.8K]

Answer:

T₂ = 305.17 K

Explanation:

Given that,

Heat, Q = 6000 J

Mass, m = 200 gram

Initial temperature, T₁ = 25° C

We need to find its final temperature. Let it is T₂.

We know that,

Q=mc\Delta T

Where

c is the specific heat of water, c = 4.18 J/g°C

So,

6000=200\times 4.18\times (T_2-298)\\\\\dfrac{6000}{200\times 4.18}=(T_2-298)\\\\7.17=(T_2-298)\\\\7.17+298=T_2\\\\T_2=305.17\ K

So, the final temperature is equal to 305.17  K.

3 0
3 years ago
The mass of an electron is about 9.11 × 10-31 kg. Write this as a whole number
galina1969 [7]

Answer:

1 electron has a mass of 9.1 X 10-31 kg. How many electrons n does it take to make 1 kg?

(1 e)/(9.1 X 10-31 kg) = n/(1 kg)

So, n = 1.10 X 1030 electrons

Each electron has a charge of 1.6 X 10-19 C, where C stands for Coulombs. So, the n electrons have a charge of q = ne = (1.10 X 1030 electrons) X (1.6 X 10-19 C/electron) = 1.76 X 1011 C. This is an insane charge!

The electrostatic force between two of these 1kg bundles of electrons is given by Coulomb's law:

F = k qq/r2 = (8.99 X 109)(1.76 X 1011 C)2/(1000 m)2 = 2.78 X 1026 N.

7 0
3 years ago
Read 2 more answers
If Mercury, moved two orbital paths closer to the sun: what would be different? List serval differences, ideas.......
elena-14-01-66 [18.8K]
Well first of all, when it comes to orbits of the planets around
the sun, there's no such thing as "orbital paths", in the sense
of definite ("quantized") distances that the planets can occupy
but not in between.  That's the case with the electrons in an atom,
but a planet's orbit can be any old distance from the sun at all. 

If Mercury, or any planet, were somehow moved to an orbit closer
to the sun, then ...

-- its speed in orbit would be greater,

-- the distance around its orbit would be shorter,

-- its orbital period ("year") would be shorter,

-- the temperature everywhere on its surface would be higher,

-- if it has an atmosphere now, then its atmosphere would become
less dense, and might soon disappear entirely,

-- the intensity of x-rays, charged particles, and other forms of
solar radiation arriving at its surface would be greater.
5 0
3 years ago
What is the constant snell’s law
Marat540 [252]

Snell's law is defined as “The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given colour and for the given pair of media”.

3 0
3 years ago
1. A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly hori
Dovator [93]

Answer:

The net acceleration of the SUV is 0.429 meters per square second due west.

Explanation:

Statement is incomplete. Description is presented below:

<em>A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly horizontal road. The surface of the road exerts a resistance force of 500 N due east. At the same time a high wind is blowing a force of 500 N due east in the opposite direction of the car's drive force. Does the car has any acceleration? If yes, then what are the magnitude and direction of the car's acceleration?</em>

According to Newton's Laws of Motion, the SUV will accelerate if and only if net acceleration is different of zero. Let suppose as positive the direction of driving force (F), measured in newtons:

\Sigma F = F - R -f = F_{net} (1)

Where:

R - Resistance force, measured in newtons.

f - Wind force, measured in newtons.

F_{net} - SUV net force, measured in newtons.

If we know that F = 2500\,N, R = 500\,N and f = 500\,N, then net force experimented by the SUV is:

F_{net} = 2500\,N-500\,N-500\,N

F_{net} = 1500\,N

The car has acceleration.

By definition of force for systems with constant mass, we calculate the acceleration of the vehicle below:

a_{net} = \frac{F_{net}}{m} (2)

Where m is the mass of the SUV, measured in kilograms.

If we know that F_{net} = 1500\,N and m = 3500\,kg, then the net acceleration of the car is:

a_{net} = \frac{1500\,N}{3500\,kg}

a_{net} = 0.429\,\frac{m}{s^{2}}

The net acceleration of the SUV is 0.429 meters per square second due west.

8 0
3 years ago
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