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Aloiza [94]
3 years ago
12

Find the Highest Common Factor of : 27, 36, and 54.​

Mathematics
1 answer:
faust18 [17]3 years ago
6 0

Answer: 9

Step-by-step explanation:

The factors of 27 are: 1, 3, 9, 27

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 54 are: 1, 2, 3, 6, 9, 18, 27, 54

Then the greatest common factor is 9.

Hope this helped ! :)

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Solve for the variable in the following equation: 1 / 6c + 1 / 3 = - 2
tankabanditka [31]

Answer: C. C=-14

Step-by-step explanation:

Given

(1/6)c+1/3=-2

Multiply both sides by the LCM of 1/6 and 1/3(Least Common Multiple)

6[(1/6)c+1/3]=(-2)(6)

c+2=-12

Subtract 2 on both sides

c+2-2=-12-2

c=-14

Hope this helps!! :)

Please let me know if you have any questions

4 0
2 years ago
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Laura picked a crayon randomly from a box, recorded the color, and then placed it back in the box. She repeated the process and
ruslelena [56]
The answer is B. The next crayon Laura picks is NOT red.
8 0
3 years ago
Jennys room is 13 feet long and 12 feet wide, Ruth's room is 14 feet long and 11 feet wide, whose room has the greater area?
meriva

Answer:

Jenny's room

Step-by-step explanation:

13x12 = 156 and 14x11 = 154

Therefore Jenny's room is bigger.

6 0
3 years ago
Use the discriminant to find the number and type of solution for x^2+6x=-9​
likoan [24]

Answer:

D = 0; one real root

Step-by-step explanation:

Discriminant Formula:

\displaystyle \large{D =  {b}^{2}  - 4ac}

First, arrange the expression or equation in ax^2+bx+c = 0.

\displaystyle \large{ {x}^{2}  + 6x =  - 9}

Add both sides by 9.

\displaystyle \large{ {x}^{2}  + 6x + 9 =  - 9 + 9} \\  \displaystyle \large{ {x}^{2}  + 6x + 9 =  0}

Compare the coefficients so we can substitute in the formula.

\displaystyle \large{a {x}^{2}  + bx + c =  {x}^{2}  + 6x + 9 }

  • a = 1
  • b = 6
  • c = 9

Substitute a = 1, b = 6 and c = 9 in the formula.

\displaystyle \large{D =  {6}^{2}  - 4(1)(9)} \\  \displaystyle \large{D =  36 - 36} \\  \displaystyle \large{D =  0}

Since D = 0, the type of solution is one real root.

6 0
3 years ago
One half the square of a number is less than a second number. The sum of 3 and the opposite of the second number is greater than
Ivanshal [37]

Answer: D

Step-by-step explanation:

7 0
3 years ago
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