So what you do is create a table for this example label the x values say -2 through 2. Then you plug in the x value to the equation so for 2 its <u>y=</u><u> </u><u>2</u><u>(</u><u>2</u><u>)</u><u>+</u><u>5</u> which is 9. Continue this for the rest of the graph and that should do it.
Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.
Suppose that
P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68
From the above we can find out
P(A) =
P(B) =
P(AUB) = 0.68 =
a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30
b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates
= P(A)-P(AB)+P(B)-P(AB)
c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates
When you find the sum of a number you are adding two or more numbers together. therefore the only answer that you could use to get a sum of 5 when your first term is 12 would be -7