Answer:
(0, -3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
6x - 5y = 15
x = y + 3
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 6(y + 3) - 5y = 15
- Distribute 6: 6y + 18 - 5y = 15
- Combine like terms: y + 18 = 15
- [Subtraction Property of Equality] Subtract 18 on both sides: y = -3
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define original equation: x = y + 3
- Substitute in <em>y</em>: x = -3 + 3
- Add: x = 0
Answer:
1200
Step-by-step explanation:
2 times 6 = 12
12 times 100 = 1200
Hope this helps if does not please let me know thanks!
2(n-2)=9
That's the answer. U just set it up as it is written
Answer:
Step-by-step explanation:
To find the inverse of function y=f(x), swap variables and then solve for the original variable.
![y=(x-5)^3+1\\ \\ x=(y-5)^3+1\\ \\ x-1=(y-5)^3\\ \\ \sqrt[3]{x-1}=y-5\\ \\ y=\sqrt[3]{x-1}+5\\ \\ f^{-1}(x)=\sqrt[3]{x-1}+5](https://tex.z-dn.net/?f=y%3D%28x-5%29%5E3%2B1%5C%5C%20%5C%5C%20x%3D%28y-5%29%5E3%2B1%5C%5C%20%5C%5C%20x-1%3D%28y-5%29%5E3%5C%5C%20%5C%5C%20%5Csqrt%5B3%5D%7Bx-1%7D%3Dy-5%5C%5C%20%5C%5C%20y%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B5%5C%5C%20%5C%5C%20f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B5)
