Volume of a cube = s³
Therefore, s³ = 512, meaning that s = 8.
The question asks what the resulting volume would be if all sides of the cube were divided by 4.
The current side measures 8, and we know that 8/4 = 2.
Thus, the resulting volume = s³ = 2³ = 8 cubic mm.
Given:
Consider the given expression is:

To find:
The simplified form of the given expression.
Solution:
We have,

Using distributive property, it can be written as:



Therefore, the correct option is A.
Answer:
it would be 4/20 I thinkk
Step-by-step explanation:
To find the surface area of the cube using the formula, you would substitute in 2 1/2 for the length of the side.
SA = 6 x 2.5 x 2.5
SA = 37.5 ft.²
You are finding the area of one face (2.5 x 2.5) and multiplying it by six because there are six groups of this.
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C




![\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]](https://tex.z-dn.net/?f=%5Ctext%7BFactor%3A%7D%5Cqquad%20%5Cqquad%20%5Cqquad%202%5Csin%20C%5Ccdot%20%5B%5Ccos%20%28A-B%29%2B%5Ccos%20%28A%2BB%29%5D)


LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C 