Answer:
A) Not mutually exclusive
Step-by-step explanation:
Given



Required
Determine if they are mutually exclusive or not
Mutually exclusive are defined by:

So, we have:

Take LCM


By comparing:
---- Calculated
---- Given
We can conclude that A and B are not mutually exclusive because:

We’re the problem bro sorry can’t help you bud
Answer:
(8+9) 3 - 1 = 50
Step-by-step explanation:
8 + 9 = 17
17 x 3 = 51
51 - 1 = 50
numerator = top part of the fraction
denominator = bottom part of the fraction
* means multiply
a.
you can only add the numerator when the denominator is the same
cant add the denominator
denominator has to be the same
1/5 = 4/20
4/20 + 7/20 = 11/20
b.
1 7/8 = 15/8
3/4 ÷ 15/8 =
3/4 * 8/15 =
24/60 = divide both top and bottom by 12 =
2/5