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wariber [46]
3 years ago
10

Please help me in the figure, m m

Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

What do the "m" 's equal? There isn't a way to solve that without more information...

Step-by-step explanation:

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PLZ HELP QUICK WILL MARK BRAINLIEST
JulijaS [17]

Answer:

21

Step-by-step explanation:

5 0
3 years ago
Glenn budgets 1/6 of his weekly allowance for entertainment. Glenn's entertainment bill is 29. What is his weekly allowance?
Nadusha1986 [10]
For this case, as you've got 1/6th, this will then mean that you have to multiply the bill (29) by 6, therefore, giving you 174. Glenn's weekly allowance is $174
4 0
4 years ago
HELP me on this please
Rzqust [24]

Answer:

angle FEA is 100°

angle AEC is 20°

angle CEG is 60°

Step-by-step explanation:

angle AEC=angle DEB=20°

angle AEG=angle FED=80°

80°-20°=60°; angle CEG=60°

angle FEA+angle AEC+ angle CEG=180°

angle FEA=100°

6 0
3 years ago
Please help . tjjhhhhhhhh
natka813 [3]

Answer:

19 -  8√3

Step-by-step explanation:

(-4 + √2)^2

= (-4)^2 + 2(-4)(√3) + √3)^2

= 16 - 8√3 + 3

= 19 -  8√3

7 0
4 years ago
Read 2 more answers
1. A water wheel rung’s height as a function of time can be modeled by the equation:
Nimfa-mama [501]

Answer:

<em>-1</em>

Step-by-step explanation:

1. A water wheel rung’s height as a function of time can be modeled by the equation:

h - 8 = -9 sin6t

(b) Determine the maximum height above the water for a rung.

Given the rung's height modeled by the equation;

h - 8 = -9 sin6t

h(t) = -9sin6t + 8

At maximum height, the velocity of the rung is zero;

dh/dt = 0

dh/dt = -54cos6t

-54cos6t = 0

cos6t = 0/-54

cos6t = 0

6t = cos^-1(0)

6t = 90

t = 90/6

t= 15

Substitute t = 15 into the expression to get the maximum height;

Recall:

h(t) = -9sin6t + 8

h(15) = -9sin6(15) + 8

h(15) = -9sin90 + 8

h(15) = -9(1)+8

h(15) = -9+8

<em>h(15) = -1</em>

<em>hence the maximum height above the water is -1</em>

4 0
3 years ago
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