Answer:
Part B: m = - 4
Part C: m=0
Step-by-step explanation:
Part B:
x^3 * y^2 * x^2 * y3 * z^m * z^5 = x^5 *y^5 * z
(1/z^-5= z^5)
x^3 * x^2 = x^5
y^2 * y^3 = y^5
z^m * z^5 = z
Z^-4 * z^5 = z
m = - 4
Part C:
m = 0 (any number to the power of 0 = 1)
Answer:
Statement 3
Step-by-step explanation:
<u>Statement 1:</u> For any positive integer n, the square root of n is irrational.
Suppose n = 25 (25 is positive integer), then
Since 5 is rational number, this statement is false.
<u>Statement 2:</u> If n is a positive integer, the square root of n is rational.
Suppose n = 8 (8 is positive integer), then
Since is irrational number, this statement is false.
<u>Statement 3:</u> If n is a positive integer, the square root of n is rational if and only if n is a perfect square.
If n is a positive integer and square root of n is rational, then n is a perfect square.
If n is a positive integer and n is a perfect square, then square root of n is a rational number.
This statement is true.
<span>0=2x+3(3x-4)-(-x+14)
Follow BEDMAS
</span><span>0=2x+9x-12-(-x+14)
</span>0=2x+9x-12+x-14
Add like terms
0=11x-12+x-14
0=12x-12-14
0=12x-26
Flip the eqaution
12x-26=0
Move -26 across the equal sign
12x=0+26
12x=26
x=26/12
x=13/6
Hope this helps! A thanks/brainiest answer would be appreciated :)
Only the last equation is vertex form