A skateboarder skates down a ramp for 3 seconds. If his initial velocity was 0.8 m/s and · his final velocity was 7 m/s, what wa
1 answer:
Answer:
The acceleration of the skateboarder is 2.067 m/s²
Explanation:
Given;
initial velocity of the skateboarder, u = 0.8 m/s
final velocity of the skateboarder, v = 7 m/s
time of motion, t = 3 s
The acceleration of the skateboarder is given as;
Therefore, the acceleration of the skateboarder is 2.067 m/s²
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Answer:
Thus, the induced current in the coil at is 9.98 A.
Explanation:
Faraday's law says
where is the number of turns and
is the magnetic flux through the square coil:
Now,
;
therefore,
is the emf induced in the coil.
Now, the loop is connected to resistance; therefore, at
Thus, the current in the coil at is 9.98 A.
Answer:
the lowest possible frequency of the emitted tone is 404.79 Hz
Explanation:
Given the data in the question;
S₁ ← 5.50 m → L
↑
2.20 m
↓
S₂
We know that, the condition for destructive interference is;
Δr = ( 2m + ) × λ
where m = 0, 1, 2, 3 .......
Path difference between the two sound waves from the two speakers is;
Δr = √( 5.50² + 2.20² ) - 5.50
Δr = 5.92368 - 5.50
Δr = 0.42368 m
v = f × λ
f = ( 2m + )v / Δr
m = 0, 1, 2, 3, ....
Now, for the lowest possible frequency, let m be 0
so
f = ( 0 + )v / Δr
f = (v) / Δr
we know that speed of sound in air v = 343 m/s
so we substitute
f = (343) / 0.42368
f = 171.5 / 0.42368
f = 404.79 Hz
Therefore, the lowest possible frequency of the emitted tone is 404.79 Hz
Answer:
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