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3 years ago

5

Consider a circuit connected in parallel with three resistors, each providing a

1 answer:

alexgriva [62]3 years ago

3 0

Answer:

I believe that it's c it's a little confusing tho

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1. What is the potential energy of a 5.0-kg

babymother [125]

Answer:

C. 98 J

Explanation:

The appropriate formula is ...

PE = mgh . . . . . m is mass; below, m is meters

PE = (5 kg)(9.8 m/s^2)(2 m) = 98 kg·m^2/s^2

PE = 98 J

5 0

3 years ago

Force F acts between two charges, q1 and q2, separated by a distance d. If q1 is increased to twice its original value and the d

Step2247 [10]

Okay, haven't done physics in years, let's see if I remember this.

So Coulomb's Law states that $F = k \frac{Q_1Q_2}{d^2}$ so if we double the charge on $Q_1$ and double the distance to $(2d)$ we plug these into the equation to find

<span> $F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}$ </span>

So we see the new force is exactly 1/2 of the old force so your answer should be $\frac{1}{2}F$ if I can remember my physics correctly.

9 0

3 years ago

Read 2 more answers

A 3250-kg aircraft takes 12.5 min to achieve its cruising

scoundrel [369]

Answer:

effeciency n = = 49%

Explanation:

given data:

mass of aircraft 3250 kg

power P = 1500 hp = 1118549.81 watt

time = 12.5 min

h = 10 km = 10,000 m

v =85 km/h = 236.11 m/s

$n = \frac{P_0}{P}$

$P_o = \frac{total\ energy}{t} = \frac{ kinetic \energy + gravitational\ energy}{t}$

kinetic energy $= \frac{1}{2} mv^2 =\frac{1}{2} 3250* 236 = 90590389.66 kg m^2/s^2$

kinetic energy $= 90590389.66 kg m^2/s^2$

gravitational energy $= mgh = 3250*9.8*10000 = 315500000.00 kg m^2/s^2$

total energy $= 90590389.66 +315500000.00 = 409091242.28 kg m^2/s^2$

$P_o =\frac{409091242.28}{750} = 545454.99 j/s$

$effeciency\ n = \frac{P_o}{P} = \frac{545454.99}{1118549.81} = 0.49$

effeciency n = = 49%

8 0

3 years ago

A diffraction grating contains 15,000 lines/inch. We pass a laser beam through the grating. The wavelength of the laser is 633 n

MatroZZZ [7]

Answer:

Recall the Diffraction grating formula for constructive interference of a light

y = nDλ/w Eqn 1

Where;

w = width of slit = 1/15000in =6.67x10⁻⁵in = 6.67x10⁻⁵ x 0.0254m = 1.69x10⁻⁶m

D = distance to screen

λ = wavelength of light

n = order number = 1

Given

y1 = ? from 1st order max to the central

D = 2.66 m

λ = 633 x 10-9 m

and n = 1

y₁ = 0.994m

Distance (m) from the central maximum (n = 0) is the first-order maximum (n = 1) = 0.994m

Q b. How far (m) from the central maximum (m = 0) is the second-order maximum (m = 2) observed?

w = width of slit = 1/15000in =6.67x10⁻⁵in = 6.67x10⁻⁵ x 0.0254m = 1.69x10⁻⁶m

D = distance to screen

λ = wavelength of light

n = order number = 1

Given

y1 = ? from 1st order max to the central

D = 2.66 m

λ = 633 x 10⁻⁹ m

and n = 2

y₂ = 0.994m

Distance (m) from the central maximum (n = 0) is the first-order maximum (n = 2) =1.99m

8 0

3 years ago

What do you get when you subtract the force of air resistance from the force<br> of gravity?

atroni [7]

Answer:

Net force

Explanation:

3 0

3 years ago

Read 2 more answers