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Anna71 [15]
3 years ago
10

How would your body be affected involuntary action.

Physics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:

the human brain is responsible for involuntary activities, such as regulating heartbeat, breathing, and blinking. Although the brain controls both voluntary and involuntary activities, different regions of the brain are devoted to each type of task.

Both involuntary and voluntary actions are controlled by the same parts of the brain. Hindbrain and midbrain control involuntary actions like salivation, vomiting, etc. All the body's voluntary actions are controlled by the motor cortex in the frontal lobe of the cerebrum.

Explanation:

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If the new moon happens on January 15th, what shape will it be on February 6th?
Jobisdone [24]

-- From January 15 to February 6 is a period of 22 days.

-- The period of the full cycle of moon phases is 29.53 days.

-- So those dates represent (22/29.53) = 74.5% of a full cycle of phases.

-- That's almost exactly 3/4 of a full cycle, so on February 6, the moon would be almost exactly at <em>Third Quarter</em>.  That's the <em>left half of a disk </em>(viewed from the northern hemisphere).

3 0
3 years ago
Two steamrollers begin 115 mm apart and head toward each other, each at a constant speed of 1.10 m/sm/s . At the same instant, a
NeX [460]

Answer:

The distance of fly travel is 115.06 m.

Explanation:

Given that,

Distance = 115 mm

Speed = 1.10 m/s

Speed of fly = 2.20 m/s

We need to calculate the relative speed

Using formula of relative speed

v=v_{1}+v_{2}

Put the value into the formula

v=1.10+1.10

v=2.20\ m/s

We need to calculate the time for the two steamrollers to meet each other

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{115}{2.20}

t=52.3\ sec

We need to calculate the distance of fly travel

Using formula of distance

d=vt

Put the value into the formula

d=2.20\times52.3

d=115.06\ m

Hence, The distance of fly travel is 115.06 m.

3 0
3 years ago
Consider two identical objects of mass m = 0.250 kg and charge q = 4.00 μC. The first charge is held in place at the origin of a
Gnom [1K]

Answer:

a = 640 m/s²

Explanation:

From work-kinetic energy principles,

The net force acting on the second object is the gravitational force and the electric force due to the first object.

So, the gravitational force on the mass is F₁ = Gm₁m₂/r² since m₁ = m₂ = m, U = -Gm²/r²

Also, the electric force on the charge is F₂ = kq₁q₂/r² since q₁ = q₂ = q, U = kq²/r²

The net Force F = ma

So, -F₁ + F₂ = F     (F₁ is negative since it is an attractive force in the negative x -direction and F₂ is positive since it is a repulsive force in the positive x- direction)

-Gm²/r² + kq²/r² = ma

ma = -Gm²/r² + kq²/r²

a = (-Gm²/r² + kq²/r²)/m

a = (-G + kq²/m²)m/r²

Since m = 0.250 kg, q = 4.00 μC = 4.00 × 10⁻⁶ C, r = 3.00 cm = 3.00 × 10⁻² m, G = 6.67 × 10⁻¹¹ Nm²/kg², k = 9 × 10⁹ Nm²/C² and a = acceleration of second mass.

Substituting the variables into the equation, we have

a = (m/r²)(-G + k(q/m)²)]

a = (0.250 kg/{3.00 × 10⁻² m}²)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(4.00 × 10⁻⁶ C/0.250 kg)²)

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(16 × 10⁻⁶ C/kg)²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(256 × 10⁻¹² C²/kg²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 2304 × 10⁻³ Nm²/kg²  ]

a = (0.250 kg/9.00 × 10⁻⁴ m)(2.304 Nm²/kg²)

a = 0.576 Nm²/kg /9.00 × 10⁻⁴ m²

a = 0.064 × 10⁴N/kg

a = 64 × 10 N/kg)

a = 640 m/s²

8 0
3 years ago
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melamori03 [73]

All three windows are the same size.

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3 years ago
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How do scientists study pollen grains to help them understand climate change?
tino4ka555 [31]

Answer: A. by analyzing and making inferences about them

Explanation:

7 0
2 years ago
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