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nasty-shy [4]
4 years ago
6

A vector is 9.55 m long and points in a -48.0 degree direction. find the x-component of the vector.

Physics
1 answer:
jeyben [28]4 years ago
6 0

Answer:

freshwater 9.5 is a long points in the 1.4 degrees direction in the response water is the only one that can be solve the problems of the anyone is

Explanation:

me me and please mark me as a friendly staff will give you 2008 give that

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Two electric charges A and B were placed facing each other at a distance of separation "r". The common electrostatic force betwe
lutik1710 [3]

Answer:

From the formula of force:

F =  \frac{kAB}{ {r}^{2} }  \\

since AB and k are constants:

F \:  \alpha  \:  \frac{1}{ {r}^{2} }  \\  \\ F =  \frac{x}{ {r}^{2} }

x is a constant of proportionality

• when force is 4N, separation distance is 1

4 =  \frac{x}{1}  \\ x = 4

therefore, equation becomes

F =  \frac{4}{ {r}^{2} }  \\

when r is doubled, r becomes 2. find F:

F =  \frac{4}{ {2}^{2} }  \\  \\ F =  \frac{4}{4}  \\  \\ { \underline{force \: is \: 1N}}

5 0
3 years ago
Ann walks 80 meters on a straight line 33degrees north of east starting at point 1. Draw Ann's path. Represent Ann's walk with a
zubka84 [21]
The x-component of Anne's path:
80 x cos(33)
= 67.1 meters
y-component of Anne's path:
80 x sin(33)
= 43.6 meters
To draw he diagram, you draw a horizontal line starting at point 1 to the right representing 67.1 meters. At the end of this line, draw a vertical line upwards representing 43.6 meters.
Connect the start of the horizontal line at point 1 to the end of the vertical line with an angle of 33° between them.
7 0
3 years ago
A 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of th
katrin [286]

Answer:

80 Joules.

Explanation:

Given that a 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of the hill with a speed of 8 m/s. During the slide, the work done by gravity is about ?

The parameters given are:

Mass M = 20 kg

Height h = 10 m

Velocity V = 8 m/s

The workdone by gravity will be equal to the total energy

At the bottom of the hill, the total energy will be equal to the maximum kinetic energy.

Maximum K.E = 1/2mv^2

K.E = 1/2 × 20 × 8

K.E = 80J

Therefore, the workdone by the gravity is equal to 80 Joules.

5 0
3 years ago
1. Which of the following air pollutants combines with haemoglobin in our blood and renders it incapable to
enyata [817]
B, Carbon monoxide is the answer :)
7 0
3 years ago
If Noah runs three laps around a 200 meter track in two minutes, what is the average speed of Noah in m/s?
devlian [24]
• 3 laps of 200 meter track = 600 meters
• 600 meters ran in 2 minutes
• 2 minutes = 120 seconds
• 600 meters / 120 seconds = 5 m/s on average
6 0
3 years ago
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