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4 years ago

A vector is 9.55 m long and points in a -48.0 degree direction. find the x-component of the vector.

Physics

1 answer:

jeyben [28]4 years ago

6 0

Answer:

freshwater 9.5 is a long points in the 1.4 degrees direction in the response water is the only one that can be solve the problems of the anyone is

Explanation:

me me and please mark me as a friendly staff will give you 2008 give that

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A steel bar of rectangular cross section (1.5 in. 2 3 .0 in.) carries a tensile load P (see fig- ure). The allowable stresses in

lukranit [14]

Explanation:

Value of the cross-sectional area is as follows.

A = $1.5 \times 2.30$

= 3.45 $in^{2}$

The given data is as follows.

Allowable stress = 14,500 psi

Shear stress = 7100 psi

Now, we will calculate maximum load from allowable stress as follows.

$P_{max} = \sigma_{a}A$

= $14500 \times 3.45$

= 50025 lb

Now, maximum load from shear stress is as follows.

$P_{max} = 2 \times \tau_{a} \times A$

= $2 \times 7100 \times 3.45$

= 48990 lb

Hence, $P_{max}$ will be calculated as follows.

$P_{max} = min((P_{max})_{\sigma}, (P_{max})_{\tau})$

= 48990 lb

Thus, we can conclude that the maximum permissible load $P_{max}$ is 48990 lb.

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4 years ago

How many days are in 345000 minutes? (Set up by dimensional analysis)

Komok [63]

239.583 days is the answer

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2 years ago

Which of these is a qualitative research method?

Alexxandr [17]

D laboratory observation

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3 years ago

Read 2 more answers

One particle has a charge of 2.15 x 10^ -9 while another particle has a charge of 3.22 x 10^ -9 If the two particles are separat

marin [14]

Answer:

B. 2.77 x $10^{-4}$ N

Explanation:

The required force can be calculated by:

F = $\frac{Kq_{1}q_{2} }{d^{2} }$

Where F is the force between the particles, K is the coulomb's constant (9 x $10^{9}$ $Nm^{2}/C^{2}$ ), $q_{1}$ is the charge on the first particle, $q_{2}$ is the charge on the second particle and $d^{2}$ is the distance between the particles.

So that:

F = $\frac{9*10^{9}*2.15*10^{-9} *3.22*10^{-9} }{(0.015)^{2} }$

= $\frac{6.2307*10^{-8} }{(2.25*10^{-4} }$

= 2.7692 x $10^{-4}$

The force between the particles is 2.77 x $10^{-4}$ N.

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3 years ago

Explain why time is an independent and position is a dependent variable in a position versus time graph.

agasfer [191]

Time can be changed in a graph but the position stay the same

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3 years ago