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Natalka [10]
3 years ago
12

To make extra money during the summer, Mr. Garber, a 66.0-kg physics teacher, paints the outside of houses while sitting on a 5.

0-kg plank suspended by three vertical cables. What is the tension in each of the three cables?
Physics
1 answer:
deff fn [24]3 years ago
6 0
The total mass of Mr. Garber and the plank is 71kg. We can find the tension in the cable by dividing the gravitational force by 3. So let's solve for the gravitational force.

F_{g} = (71kg)*(9.81m/s) = 696.51N

Next divide by three because the tension is split.

F_{T} = 696.51/3 = 232.17N

F_{T} = 232.17N
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Whitepunk [10]

Answer:

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4 0
2 years ago
8. When you see a stopped local bus (1 point)
elena55 [62]

Answer: be alert for pedestrians near the bus.

Explanation: Due to road accidents many Governments around the world has adopted and put in place certain rules and regulations with regards to road safety, this is so to prevent the or reduce the chances of accidents happening.

Road safety rules are rules and guidelines put in place by Government in order to prevent road accidents and maintain a free flow of traffic. An example of such rules is 'be alert for pedestrians near the bus ' when approaching a local bus that is stopped.

5 0
2 years ago
The basic barometer can be used to measure the height of a building. If the barometric readings at the top and at the bottom of
LekaFEV [45]

Answer:

   (h₁-h₂) = 2.30 10² m

Explanation:

The pressure depends on the height with the formula

          P = P_atm + rho g h

Let's apply this expression for the building

         P₁ = P_atm + rho_air g h₁

        P₂ = P_atm + rho_air g h₂

Subtract

        P₁ - P₂ = roh_air g (h₁ –h₂)

         

         

The measured pressure is in mm Hg to take this unit to units of pressure must be multiplied by the density of mercury and the acceleration of gravity

           P₁- P₂ = rho_Hg g (h₁-h₂) _Hg

         rho_Hg g (h₁-h₂) _Hg = roh_air g (h₁ –h₂)

          (h₁ –h₂) = rho_Hg / rho_air (h₁-h₂) _ Hg

Let's calculate

         (h₁-h₂) = 13600 / 1.18 (695-675)

         (h₁-h₂) = 2.30 10⁵ mm

Let's reduce to meter

         (h₁-h₂) = 2.30 10⁵ mm (1 m / 10³ mm)

         (h₁-h₂) = 2.30 10² m

4 0
3 years ago
To stop a car, first you require a certain reaction time to begin braking; then the car slows under the constant braking deceler
ANEK [815]

Answer:

a) t_r = 0.55 s

b) a = 5.59 m/s²

Explanation:

given,

total distance traveled by the car to stop is 56.9 m when speed of vehicle is 80 km/h or 80 × 0.278 = 22.24 m/s

total distance traveled by the car to stop is 25.7 m when speed of vehicle is 50.7 km/h or 50.7 × 0.278 = 14.09 m/s

using stopping distance formula

s_1 = v_1 t_r +\dfrac{v_1^2}{2 a}................(1)

s_2 = v_2 t_r +\dfrac{v_2^2}{2 a}..............(2)

on solving both the equation we get

a = \dfarc{v_1v_2(v_1-v_2)}{2(s_1v_2-s_2v_1)}

a = \dfarc{22.4\times 14.09(22.24-14.09)}{2(56.9\times 14.09-25.7\times 22.24)}

a = 5.59 m/s²

now reaction time calculation

t_r =\dfrac{v_1^2d_2-v_2^2d_1}{v_1v_2(v_1-v_2)}

t_r =\dfrac{22.24^2\times 25.7-14.09^2\times 56.9}{22.4\times 14.09(22.24-14.09)}

t_r = 0.55 s      

8 0
3 years ago
Find the momentum of a 25 kg object traveling at a speed of 4 m/s
White raven [17]

Answer:

100 kg*m/s

Explanation:

P = m*v

= 25*4 = 100

4 0
3 years ago
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