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4 years ago

12

To make extra money during the summer, Mr. Garber, a 66.0-kg physics teacher, paints the outside of houses while sitting on a 5.

0-kg plank suspended by three vertical cables. What is the tension in each of the three cables?

1 answer:

deff fn [24]4 years ago

6 0

The total mass of Mr. Garber and the plank is 71kg. We can find the tension in the cable by dividing the gravitational force by 3. So let's solve for the gravitational force.

$F_{g} = (71kg)*(9.81m/s) = 696.51N$

Next divide by three because the tension is split.

$F_{T} = 696.51/3 = 232.17N$

$F_{T} = 232.17N$

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During a solar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Moon between the Earth and the Sun.

lord [1]

Answer:

(a) $F_{sm} = 4.327\times 10^{20}\ N$

(b) $F_{em} = 1.983\times 10^{20}\ N$

(c) $F_{se} = 3.521\times 10^{20}\ N$

Solution:

As per the question:

Mass of Earth, $M_{e} = 5.972\times 10^{24}\ kg$

Mass of Moon, $M_{m} = 7.34\times 10^{22}\ kg$

Mass of Sun, $M_{s} = 1.989\times 10^{30}\ kg$

Distance between the earth and the moon, $R_{em} = 3.84\times 10^{8}\ m$

Distance between the earth and the sun, $R_{es} = 1.5\times 10^{11}\ m$

Distance between the sun and the moon, $R_{sm} = 1.5\times 10^{11}\ m$

Now,

We know that the gravitational force between two bodies of mass m and m' separated by a distance 'r' is given y:

$F_{G} = \frac{Gmm'_{2}}{r^{2}}$ (1)

Now,

(a) The force exerted by the Sun on the Moon is given by eqn (1):

$F_{sm} = \frac{GM_{s}M_{m}}{R_{sm}^{2}}$

$F_{sm} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 7.34\times 10^{22}}{(1.5\times 10^{11})^{2}}$

$F_{sm} = 4.327\times 10^{20}\ N$

(b) The force exerted by the Earth on the Moon is given by eqn (1):

$F_{em} = \frac{GM_{s}M_{m}}{R_{em}^{2}}$

$F_{em} = \frac{6.67\times 10^{- 11}\times 5.972\times 10^{24}\times 7.34\times 10^{22}}{(3.84\times 10^{8})^{2}}$

$F_{em} = 1.983\times 10^{20}\ N$

(c) The force exerted by the Sun on the Earth is given by eqn (1):

$F_{se} = \frac{GM_{s}M_{m}}{R_{es}^{2}}$

$F_{se} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 5.972\times 10^{24}}{((1.5\times 10^{11}))^{2}}$

$F_{se} = 3.521\times 10^{20}\ N$

7 0

3 years ago

Virtue is _______________ between the extremes of vice – excess and deficiency.

mixer [17]

<span>Having high standards and honesty in the behavior is called a virtue and the person is considered virtuous. Usually virtue is mean between two extremes as that mid ground gives a balance to the behavior. Virtues are means between the extremes of vices which are excess and deficiency.</span>

6 0

4 years ago

A train is travelling towards the station on a straight track. It is a certain distance from the station when the engineer appli

AleksandrR [38]

Answer:

500 m

Explanation:

t = Time taken

u = Initial velocity = 50 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = -2.5 m/s²

Equation of motion

$v=u+at\\\Rightarrow 0=50-2.5\times t\\\Rightarrow \frac{-50}{-2.5}=t\\\Rightarrow t=20\ s$

Time taken by the train to stop is 20 seconds

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=50\times 20+\frac{1}{2}\times -2.5\times 20^2\\\Rightarrow s=500\ m$

∴ The engineer applied the brakes 500 m from the station

4 0

3 years ago

5) Old-style dimmers consisted of a variable resistor so you could dial in more resistance to lower the current and, hence, dim

NeX [460]

Answer:

The power of the bulb is reduced to a quarter

Explanation:

The power in an electrical circuit is

P = V I = I² R

If the dimmer cuts the current in half

I = I₀ / 2

The resistance of the light bulb after hot is little affected by small changes in the current

We substitute in the equation

P = I₂ R

P = (I₀ /2)² R

P = ¼ I₀² R

P = ¼ P₀

The power of the bulb is reduced to a quarter

4 0

4 years ago

the mass of a proton is 1.6726 * 10^-24 and the mass of a electron is 9.1093 * 10^-28. What is the difference between the mass o

crimeas [40]

Proton : 0.00000000000000000000000161726

Electron : 0.00000000000000000000000000091093

Take them away =
1.616349e−24
(that's what it gave me on the calculator when I did proton - electron)

3 0

3 years ago

Read 2 more answers