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Natalka [10]
3 years ago
12

To make extra money during the summer, Mr. Garber, a 66.0-kg physics teacher, paints the outside of houses while sitting on a 5.

0-kg plank suspended by three vertical cables. What is the tension in each of the three cables?
Physics
1 answer:
deff fn [24]3 years ago
6 0
The total mass of Mr. Garber and the plank is 71kg. We can find the tension in the cable by dividing the gravitational force by 3. So let's solve for the gravitational force.

F_{g} = (71kg)*(9.81m/s) = 696.51N

Next divide by three because the tension is split.

F_{T} = 696.51/3 = 232.17N

F_{T} = 232.17N
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A paper filled capacitor is charged to a potential difference of 2.1 V and then disconnected from the charging circuit. The diel
Goryan [66]

Answer:

Part a)

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Part b)

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So we will have

Q = kC(2.1)

now dielectric is removed between the plates of capacitor

so new potential difference between the plates

V' = \frac{Q}{C'}

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Part b)

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So again charge is same so potential difference is given as

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5 0
3 years ago
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slava [35]

Answer:

b. The side the boy is sitting on will tilt downward

Explanation:

Initially, the seesaw is balanced because the torque exerted by the boy is equal to the torque exerted by the girl:

\tau_b = \tau_g\\W_b d_b = W_g d_g

where

Wb is the weight of the boy

db is the distance of the boy from the pivot

Wg is the weight of the girl

dg is the distance of the girl from the pivot

When the boy moves backward, the distance of the boy from the pivot ((d_b) increases, therefore the torques are no longer balanced: the torque exerted by the boy will be larger, and therefore the side of the boy will tilt downward.

5 0
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