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Lelechka [254]
3 years ago
8

How many meters will a car travel if its speed is 45 m/s in an interval of 11 seconds?

Physics
2 answers:
maks197457 [2]3 years ago
5 0

Data given:

V=45m/s

t=11s

Δx=?

Formula needed:

V=Δx/t

Solution:

Δx=v×t

Δx=45m/s×11s

Δx=495m

According to my solution B) is the most accurate

MaRussiya [10]3 years ago
3 0
495 is the answer !!
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Can anyone please tell me the properties of image formed in a spherical mirror?
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Answer:

The two rays, CY and DM are diverging rays and when extended behind the mirror, they appear to intersect each other at point M'. Therefore, the properties of the images formed here are formed behind the mirror, between the pole and principal focus (f), the images are diminished and are virtual and erect.

Explanation:

<h2>Spherical Mirrors</h2>

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6 0
3 years ago
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Use Coulomb’s law to derive the dimension for the permittivity of free space. <br><br><br><br>​
MrRa [10]

Answer:

Coulomb's law is:

F = \frac{1}{4*pi*e0} *(q1*q2)/r^2

First, force has units of Newtons, the charges have units of Coulombs, and r, the distance, has units of meters, then, working only with the units we have:

N = (1/{e0})*C^2/m^2

then we have:

{e0} = C^2/(m^2*N)

And we know that N = kg*m/s^2

then the dimensions of e0 are:

{e0} = C^2*s^2/(m^3)

(current square per time square over cubed distance)

And knowing that a Faraday is:

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The units of e0 are:

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7 0
3 years ago
Twopucksofequalmasscollideonafrictionlesssurface,asillustratedinthefigure.Immediatelyafterthe collision, the speed of the black
seropon [69]

Answer:

The speed of the white puck immediately after the collision is 2.6 m/s.

Explanation:

Given that,

Two pucks are equal masses.

Speed of black puck = 1.5 m/s

According to given figure,

We need to calculate the speed of the white puck immediately after the collision

Using law of conservation of momentum

mv=m_{1}v_{1}\cos\theta+m_{2}v_{2}\cos\theta

Put the value into the formula according to figure

m\times3=m\times v_{1}\times\cos30+m\times1.5\times\cos60

3m=0.866m v_{1}+0.75m

v_{1}=\dfrac{3-0.75}{0.866}

v_{1}=2.6\ m/s

Hence, The speed of the white puck immediately after the collision is 2.6 m/s.

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