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Lelechka [254]
3 years ago
8

How many meters will a car travel if its speed is 45 m/s in an interval of 11 seconds?

Physics
2 answers:
maks197457 [2]3 years ago
5 0

Data given:

V=45m/s

t=11s

Δx=?

Formula needed:

V=Δx/t

Solution:

Δx=v×t

Δx=45m/s×11s

Δx=495m

According to my solution B) is the most accurate

MaRussiya [10]3 years ago
3 0
495 is the answer !!
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What is the gravitational force between 90kg man and his 35 kg dog when they are 3m apart ?
MariettaO [177]

Answer:

40 kilo grammes ...............

3 0
3 years ago
The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?
BigorU [14]

1. Frequency: 7.06\cdot 10^{14} Hz

The frequency of a light wave is given by:

f=\frac{c}{\lambda}

where

c=3\cdot 10^{-8} m/s is the speed of light

\lambda is the wavelength of the wave

In this problem, we have light with wavelength

\lambda=425 nm=425\cdot 10^{-9} m

Substituting into the equation, we find the frequency:

f=\frac{c}{\lambda}=\frac{3\cdot 10^{-8} m/s}{425\cdot 10^{-9} m}=7.06\cdot 10^{14} Hz


2. Period: 1.42 \cdot 10^{-15}s

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

The frequency of this light wave is 7.06\cdot 10^{14} Hz (found in the previous exercise), so the period is:

T=\frac{1}{f}=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s


4 0
3 years ago
Read 2 more answers
For general projectile motion, when the projectile is at the highest point of its trajectory, its acceleration is zero? A)The ho
Daniel [21]

Answer:

B) Its velocity is perpendicular to the acceleration.

Explanation:

For general projectile motion, the horizontal acceleration is 0 and the vertical acceleration is -g.  This is true for all points on the trajectory.

At the highest point, the vertical velocity is 0.  So you have only a horizontal velocity as well as a vertical acceleration.  So the two are perpendicular.

4 0
3 years ago
A proton moves from left to right across the screen at speed v0. Then a uniform magnetic field of strength 0.80 T is directed in
Anton [14]

Answer: The force is  directed upward

Explanation: Considering the Lorentz force, given by:

F= qv×B

using the right hand rule and considering the direction of electron velocity and the magnetic field from the figure, the vectorial product gives a  force vector upwards .

8 0
4 years ago
calculate minimum number of incident photons per area and of the minimum dose needed to visualize an object of 1 mm squared usin
Lynna [10]

Answer:

minimum number of photon is 4.05 × 10^{7}

Explanation:

given data

energy = 50 keV = 50 × 10^{3} eV =  50 × 10^{3} × 1.602× 10^{-19}  J

thickness = 10^-3

contrast = 1%

to find out

number of incident photons

solution

we know here equation that is

E  = n  × h  × ν   .......................1

put here all these value

50 × 10^{3} = n × 6.6× 10^{-34} × c/ 1× 10^{-3}

50 × 10^{3} × 1.602× 10^{-19}  = n × 6.6× 10^{-34} ×( 3 × 10^{8} / 1× 10^{-3})

solve it and find n

n = 4.05 × 10^{7}

so here minimum number of photon is 4.05 × 10^{7}

3 0
3 years ago
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