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Lelechka [254]
3 years ago
8

How many meters will a car travel if its speed is 45 m/s in an interval of 11 seconds?

Physics
2 answers:
maks197457 [2]3 years ago
5 0

Data given:

V=45m/s

t=11s

Δx=?

Formula needed:

V=Δx/t

Solution:

Δx=v×t

Δx=45m/s×11s

Δx=495m

According to my solution B) is the most accurate

MaRussiya [10]3 years ago
3 0
495 is the answer !!
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A bowling ball encounters a 0.760 m vertical rise on the way back to the ball rack. Ignore frictional losses and assume the mass
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To solve this exercise we need the concept of Kinetic Energy and its respective change: Initial and final kinetic energy.

Let's start considering that the angular velocity is given by,

\omega = \frac{v}{R}

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R = the radius

In the case of the initial kinetic energy:

KE_i=\frac{1}{2} mv^2 + \frac{1}{2}I \omega^2

Where I is the moment of inertia previously defined.

KE_i = \frac{1}{2}(m)3.5^2 + \frac{1}{2}* (\frac{2}{5} m R^2) (\frac{3.5}{R})^2

In the case of the final kinetic energy, we have to,

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KE_f = m * 9.81 * 0.76 + \frac{1}{2} m v^2 + \frac{1}{2} (\frac{2}{5} m R^2) (\frac{v}{R})^2

For conservation of Energy we have, that

KE_f = KE_i, then (canceling the mass and the radius)

\frac{1}{2} 3.5^2 + \frac{1}{2}(\frac{2}{5})(3.5)^2= 9.81 * 0.76 + \frac{1}{2} v^2 + \frac{1}{2} (\frac{2}{5}) (v)^2

8.575= 7.4556+ \frac{1}{2} v^2 + \frac{1}{2} (\frac{2}{5}) (v)^2

1.1194= \frac{1}{2}( v^2 + (\frac{2}{5}) (v)^2)

2.2388= (\frac{7}{5}) (v)^2

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7 0
3 years ago
Changing the food given to hamsters causes different weight gain. why is this hypothesis bad?
timama [110]
This is a bad hypothesis because it's a statement. It is a description of what occurs, not a question that you will experiment upon to find an answer whether or not something will or will not be true.
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3 years ago
How are amplitude, intensity, and<br> loudness related?
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