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Lelechka [254]
3 years ago
8

How many meters will a car travel if its speed is 45 m/s in an interval of 11 seconds?

Physics
2 answers:
maks197457 [2]3 years ago
5 0

Data given:

V=45m/s

t=11s

Δx=?

Formula needed:

V=Δx/t

Solution:

Δx=v×t

Δx=45m/s×11s

Δx=495m

According to my solution B) is the most accurate

MaRussiya [10]3 years ago
3 0
495 is the answer !!
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Since all stars begin their lives with the same basic composition, what characteristic most determines how they will differ?
Dafna1 [17]
4. Mass they are formed with
7 0
3 years ago
A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat
Gekata [30.6K]

Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}

\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}

\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}

Using Newton's second law, it is established that  F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object \left(m_{1}+m_{2}\right)

Now consider both \mathrm{m}_{1} \text { and } \mathrm{m}_{2}as a system, so net force acting on the system is \text { Force }=\left(m_{1}+m_{2}\right) a

Substitute the given values in the above formula,

\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

Force = 1215 N

<u>1215 N </u>is the force required to move the quarterback with linebacker.

5 0
3 years ago
a coil of 40 henry inductance is connected in series with aresistance of 8ohm and the combination is joined to the terminals of
Andreyy89

Answer: 5 seconds

Explanation:

Given the following :

Inductance (L) = 40 henry

Resistance = 8 ohms

The circuit given above is a Resistor - Inductor (RL) circuit network. The time constant of an RL circuit is the ratio of the circuit Inductance (L) and Resistance (R). Time constant is measured in seconds.

THAT IS;

Time constant = L / R

THEREFORE ;

Time constant = 40 / 8

Time constant = 5 seconds

7 0
3 years ago
You measure the magnetic field of a long, current-carrying wire to be B is equal to start fraction 50 times mu naught over pi en
FromTheMoon [43]

Answer:

  I = 1.875 A

Explanation:

For this exercise we use Ampere's law

             ∫ B . ds = μ₀  I

We use a circular path around the wire whereby B and ds are parallel, whereby the dot product is reduced to the algebraic product

               ds = 2π dr

               B (2πr) = μ₀  I

              I = B 2π R /μ₀  

              r= 7.5 cm = 0.075 m

calculate

             I = (50 μ₀ /π) 2π 0.075 /μ₀  

             I = 1.875 A

           

5 0
3 years ago
Beryllium (Be) and fluorine (F) combine to make the compound BeF. What is the chemical name for this compound?
kvv77 [185]

Answer:

Option A

Beryllium fluoride

Explanation:

The combination of Beryllium (Be) and Fluorine (F) leads to formation of a compound called Beryllium fluoride (BeF). The name is changed to fluoride and not fluorine because the salts of fluorine are called fluoride salts. Beryllium has oxidation state of +2 being a metal with atomic number 4. Fluorine is the lightest halogen and known to be the most electronegative element due to its high affinity to attract electrons and it has atomic number 9. The combination of Be and F is a salt.

6 0
2 years ago
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