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ELEN [110]
3 years ago
6

A paper airplane with mass 0.1 kg is flying 1.5 m above the ground with a speed of 2 m/s. What is the total mechanical energy of

the paper airplane?
Physics
2 answers:
Wewaii [24]3 years ago
7 0
Total mechanical energy = kinetic energy + potential energy
E = KE + PE
E = ½mv² + mgh
E = ½(0.1 kg)(2 m/s)² + (0.1 kg)(9.8 m/s²)(1.5 m)
E = 0.2 J + 1.47 J
E = 1.67 J
timama [110]3 years ago
4 0
We know that:
EM=Epg+Ek
So:
Epg=mgh
Epg=0,1kg*9,8m/s²*1,5m
Epg=1,47J
Now:
Ek=1/2mv²
Ek=1/2(0,1kg)(2m/s)²
Ek=0,2J
That give us:
EM=1,47J*0,2J
EM=1,67J
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Answer:

Decreases by $3.6 \times 10^{-3}$ times

Explanation:

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The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.

In other words, the sound intensity decreases as inversely proportional to the squared of the distance.  i.e. $\frac{1}{r^2}$

In the context when the distance was 3 m, the intensity of the sound was = $\frac{1}{9}$

But when the distance became 6 cm or 0.06 m, the sound intensity decreases by =  $\frac{1}{0.06^2}$

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3 years ago
A battery is used to charge a parallel-plate capacitor, after which it is disconnected. Then the plates are pulled apart to twic
Igoryamba

Answer: C.

Explanation:

For a parallel-plate capacitor where the distance between the plates is d.

The capacitance is:

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You can see that the distance is in the denominator, then if we double the distance, the capacitance halves.

Now, the stored energy can be written as:

E = (1/2)*Q^2/C

Now you can see that in this case, the capacitance is in the denominator, then we can rewrite this as:

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e is a constant, A is the area of the plates, that is also constant, and Q is the charge, that can not change because the capacitor is disconnected.

Then we can define:

K = (1/2)*Q^2/(e*A)

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<span>s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160. </span>

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