we can convert any decimal value to a fraction by simply <u>using in the denominator a power of 10 with as many zeros as there are decimals and lost the dot above</u>, this one has one decimal, so we'll use 1 zero, and lose the dot above.
![\bf 0.\underline{6}\implies \cfrac{06}{1\underline{0}}\implies \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 3}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 50}\implies \cfrac{3}{50}](https://tex.z-dn.net/?f=%5Cbf%200.%5Cunderline%7B6%7D%5Cimplies%20%5Ccfrac%7B06%7D%7B1%5Cunderline%7B0%7D%7D%5Cimplies%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%202%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%5Ccdot%203%7D%7B~~%5Cbegin%7Bmatrix%7D%202%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%5Ccdot%2050%7D%5Cimplies%20%5Ccfrac%7B3%7D%7B50%7D)

<u>We </u><u>have </u><u>given </u><u>in </u><u>the </u><u>question </u><u>that</u><u>, </u>
- <u>The </u><u>sum </u><u>of </u><u>2</u><u> </u><u>numbers </u><u>is </u><u>equal </u><u>to </u><u>1</u><u>1</u><u> </u>
- <u>The </u><u>difference </u><u>between </u><u>two </u><u>numbers </u><u>is </u><u>1</u><u>9</u><u> </u><u>.</u>

- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y</u><u>. </u>

Let the two numbers be x and y
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>


<u>Solving </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>


<u>Subsituting </u><u>eq(</u><u>3</u><u> </u><u>)</u><u> </u><u>in </u><u>eq</u><u>(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>









<u>Now</u><u>, </u><u> </u><u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>3</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>




Hence, The value of x and y are 15 and (-4) .
Answer:
Neither for 1
the second option for 2
Step-by-step explanation:
not sure how to explain this