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Tema [17]
3 years ago
15

How might we know whether X is a positive number negative number or 0 without solving the equation 5x=-16.5

Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer:

Since 16.5 is negative, the only way to get that answer is to multiply 5 by something to negative(x)

Step-by-step explanation:

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HELPP PLEASEE! pleaseeeeee
vfiekz [6]

Answer:

a = 14 km

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh  where b is the base and h is the height

112.7 = 1/2 ( a) 16.1

112.7 = 8.05a

Divide each side by 8.05

112.7/8.05 = a

14 =a

a = 14 km

3 0
2 years ago
Image point N'(12, -6) was dilated from the pre-image point N(4, -2). What was the scale factor used?
skelet666 [1.2K]
The scale factor's 3 since 12 and 4 can be divided by 3 and -6 and -2 can also be divided by 3.
7 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
4 years ago
Jan has a piece of yarn that is 6 1/2 feet long. She cuts off a piece that is 2 5/12 feet long. How much yarn does she have left
icang [17]
The answer is b because all you have to do is just subtract if I am wrong so sorry
5 0
3 years ago
Please see below!! Thank you so much in advance :)
stellarik [79]

Answer:

a) x = -1.9, 1.05

b) x = -3, 0, 2

Explanation:

I hope it's correct

7 0
2 years ago
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