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mezya [45]
3 years ago
13

What is the outre layer and large part of the sun´s atmosphere

Chemistry
1 answer:
Nadusha1986 [10]3 years ago
7 0

Answer:

Our Sun. Corona – The outer layer of sun's atmosphere. Sunspot – A dark area of gas on the sun's surface that is cooler than surrounding gases. Prominence – A huge, reddish loop of gas that protrudes from the sun's surface, linking part of sunspot regions.

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Explain how atomic interactions determine a material to be transparent and opaque
mote1985 [20]

Answer:

The materials are opaque or crystalline from a client to the orientation and type of union between their atoms, forming two types of structures.

These two structures can be crystalline or amorphous.

In the case of being crystalline, these unions do not allow light to pass through the medium of the object or body of said compound, making it totally refract and giving the appearance of OPAQUE.

On the other hand, in those compounds that we call amorphous, the atoms are located in a different way that makes light pass through them, without absorbing or identifying any light beam, so they look transparent.

Explanation:

Example: A glass cup has an amorphous structure, while a porcelain or porcelain plate has a crystalline structure.

5 0
3 years ago
Which of the following weak interactions would require the least amount of energy to disrupt? Group of answer choices
SpyIntel [72]

Answer: Option (c) is the correct answer.

Explanation:

A hydrogen bond is defined as a weak bond that is formed between an electropositive atom (generally hydrogen atom) and an electronegative atom like oxygen, nitrogen and fluorine.

An ionic bond is defined as a bond formed between a metal and a non-metal and in this bond transfer of electron takes place from metal to non-metal. And, due to the presence of opposite charges on the combining atoms there exists a strong force of attraction.

Vander waal forces are defined as the weak electric forces which tend to attract neutral molecules towards each other in gases, liquefied and solidified gases.

Vander waal forces are very weak forces.

Thus, we can conclude that Van der walas interactions are weak interactions would require the least amount of energy to disrupt.

8 0
3 years ago
Read 2 more answers
What is the mole fraction of water in pure water
irinina [24]
In pure water, all of the molecules in the liquid are water molecules so the mole fraction is 1 (100 % H2O, 55 mol/L). In sea water, the concentration of water molecules in the solution is less than that of pure water so the vapor pressure of sea water is also lower.
5 0
3 years ago
Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample
goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=2:2=1:1

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=3:3=1:1

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.


4 0
3 years ago
1. What is the potential energy of a 8 kg ball that is at a height of 20 m?
weqwewe [10]

Answer:

1. 1568 J

2. 0 J

3. 1176 J

Explanation:

PE = mgh

(PE = Potential Energy) = (m = mass)(g = gravitational force which is 9.8)(h = height)

1. (3)(9.8)(20) = 1568 J

2. PE = (3)(9.8)(0) = 0 J

3. (5)(9.8)(24) =  1176 J

4 0
3 years ago
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