To determine the amount of oxygen that is present in the compound, we have to assume that the given compound contains carbon, hydrogen and oxygen only or else we will not be able to determine the answer. We need to convert the moles of the elements given to units of grams by using the atomic mass of these elements. Then, from the total amount of the compound we subtract the masses of the elements. We do as follows:
mass
0.117 mol C ( 12.01 g / 1 mol ) = 1.41 g
0.233 mol H ( 1.01 g / 1 mol ) = 0.24 g
Mass O = 3.50 g - 1.41 g - 0.24 g = 1.85 g O
Moles O = 1.85 g O ( 1 mol / 16 g ) = 0.116 moles O
This answer would be a blood vessels
Answer is: <span>volume of 1 M NaOH is 1 ml.
</span>c₁(NaOH) = 1 M.
V₂(NaOH) = 10 ml.
c₂(NaOH) = 0,1 M.
V₁(NaOH) = ?
c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - <span>volume to be diluted.
V</span>₂ - <span>final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂.
V₁(NaOH) = c₂ · V₂ ÷ c₁.
V₁(NaOH) = 0,1 M · 10 ml ÷ 1 M.
V₁(NaOH) = 1 ml.
Answer:
litre.50000665432158900643212lo
Answer: Option (d) is the correct answer.
Explanation:
It is known that length of a bond is inversely proportional to the bond strength. This also means that a single bond has long length due to which it is weak in nature.
And, a double bond is shorter in length and has more strength as compared to a single bond. Whereas a triple bond has the smallest length and it has high strength as compared to a double or single bond.
For example, carbon monoxide is CO where there is a triple bond between the carbon and oxygen atom.
Carbon dioxide is 
where there exists a double bond between the carbon and oxygen atom.
A carbonate ion is 
when two oxygen atoms are attached through single bond with the carbon atom and another oxygen atom is attached through a double bond to the carbon atom.
Hence, we can conclude that order of increasing bond strength of the given carbon oxygen bond is as follows.
Carbonate ion < carbon dioxide < carbon monoxide
