Water moves through the help of living organisms in an ecosystem. ... Plants absorbs water through their root system and loss by transpiration. Water also moves through the living organisms in an ecosystem. Other nonliving processes such as evaporation, precipitation, water returns back into the atmosphere.

Explanation:

hope this helps you

5 0

2 years ago

Read 2 more answers

Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of

bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

$O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol$ ..[1]

$O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol$ ..[2]

$NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol$ ..[3]

$NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?$ ..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

$2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}$

$2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol$

$2\times \Delta H^o_{4}=470.3 kJ/mol$

$\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol$

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0

3 years ago

6. The nuclear reaction where Si-30 becomes P-30 is

Arisa [49]

Answer:c

Explanation:

8 0

3 years ago

How many grams of ethane gas (C2H6) are in a 12.7 liter sample at 1.6 atmospheres and 24°C? Show all work used to solve this pro

dexar [7]

n = PV/RT

p = 1.6 atm

v = 12.7L

R = 0.0821

T = 24°C which is equivalent to 297.15 degrees k

n = (16 × 12.7) / (0.0821 × 297.15)

n = 20.32 / 24.39

n = 0.83 mol

C = 12.90

H = 1.0079

C2 = 12.010 × 2 = 24.02

H6 = 1.0079 × 6 = 6.0474

C2H6 = 30.0674

Ethane times n which is 30.0674 × 0.83mol

= 24.95 grams of C2H6. Which is Ethane.

4 0

3 years ago