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3 years ago

Why is ionic bonding considered a bond type and an attractive force?

Chemistry

1 answer:

Anika [276]3 years ago

7 0

Answer:

Ionic bonding is a type of chemical bond in which valence electrons are lost from one atom and gained by another. This exchange results in a more stable, noble gas electronic configuration for both atoms involved. An ionic bond is based on attractive electrostatic forces between two ions of opposite charge.

Explanation:

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belka [17]

these what, these nutz??

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3 years ago

The ph of 0.010 m aqueous aniline is 8.32. What is the percentage protonated?

LekaFEV [45]

Answer : The percentage aniline protonated is, 0.0209 %

Explanation :

First we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-8.32\\\\pOH=5.68$

Now we have to calculate the hydroxide ion concentration.

$pOH=-\log [OH^-]$

$5.68=-\log [OH^-]$

$[OH^-]=2.09\times 10^{-6}M$

The equilibrium chemical reaction will be:

$NH_3+H_2O\rightleftharpoons NH_4^++OH^-$

From the reaction we conclude that,

Concentration of $OH^-$ ion = Concentration of $NH_4^+$ ion = $2.09\times 10^{-6}M$

Now we have to calculate the percentage aniline protonated.

$\text{percentage aniline protonated}=\frac{2.09\times 10^{-6}M}{0.010M}\times 100$

$\text{percentage aniline protonated}=0.0209\%$

Thus, the percentage aniline protonated is, 0.0209 %

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3 years ago

Would magnesium prefer to lose or gain electrons

slega [8]

Umm what kind of question is that but i think gain lol

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3 years ago

Match the word with its definition.

DiKsa [7]

Mass = that which causes and object to have inertia

Newton’s First Law= a special case of Galileo’s Law of Inertia

Impulse= force multiplied by time

Momentum= velocity multiplied by mass

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Newton’s Second Law= the acceleration of a mass directly proportional to the force acting on it

7 0

4 years ago

Read 2 more answers

A solution was prepared by dissolving 195.0 g of KCl in 215 g of water. Calculate the mole fraction of KCl. (The formula weight

defon

Answer:

Approximately $0.180$ .

Explanation:

The mole fraction of a compound in a solution is:

$\displaystyle \frac{\text{Number of moles of compound in question}}{\text{Number of moles of all particles in the solution}}$ .

In this question, the mole fraction of $\rm KCl$ in this solution would be:

$\displaystyle X_\mathrm{KCl} = \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}$ .

This solution consist of only $\rm KCl$ and water (i.e., $\rm H_2O$ .) Hence:

$\begin{aligned} X_\mathrm{KCl} &= \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}\\ &= \frac{n(\mathrm{KCl})}{n(\mathrm{KCl}) + n(\mathrm{H_2O})}\end{aligned}$ .

From the question:

Mass of $\rm KCl$ : $m(\mathrm{KCl}) = 195.0\; \rm g$ .
Molar mass of $\rm KCl$ : $M(\mathrm{KCl}) = 74.6\; \rm g \cdot mol^{-1}$ .

Mass of $\rm H_2O$ : $m(\mathrm{H_2O}) = 215\; \rm g$ .
Molar mass of $\rm H_2O$ : $M(\mathrm{H_2O}) = 18.0\; \rm g\cdot mol^{-1}$ .

Apply the formula $\displaystyle n = \frac{m}{M}$ to find the number of moles of $\rm KCl$ and $\rm H_2O$ in this solution.

$\begin{aligned}n(\mathrm{KCl}) &= \frac{m(\mathrm{KCl})}{M(\mathrm{KCl})} \\ &= \frac{195.0\; \rm g}{74.6\; \rm g \cdot mol^{-1}} \approx 2.61\; \em \rm mol\end{aligned}$ .

$\begin{aligned}n(\mathrm{H_2O}) &= \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} \\ &= \frac{215\; \rm g}{18.0\; \rm g \cdot mol^{-1}} \approx 11.9\; \em \rm mol\end{aligned}$ .

The molar fraction of $\rm KCl$ in this solution would be:

$\begin{aligned} X_\mathrm{KCl} &= \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}\\ &= \frac{n(\mathrm{KCl})}{n(\mathrm{KCl}) + n(\mathrm{H_2O})} \\ &\approx \frac{2.61 \; \rm mol}{2.61\; \rm mol + 11.9\; \rm mol} \approx 0.180\end{aligned}$ .

(Rounded to three significant figures.)

8 0

3 years ago