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BlackZzzverrR [31]
3 years ago
6

Balancing H2SO4+NH4OH —> H2O+(NH4)2SO4

Chemistry
1 answer:
azamat3 years ago
3 0

H₂SO₄   +    2NH₄OH    →     (NH₄)₂SO₄   +    2H₂O

Explanation:

  Unbalanced reaction equation:

                    H₂SO₄   +    NH₄OH    →     (NH₄)₂SO₄   +    H₂O

We can use a simple mathematical approach to balance this equation by solving simple algebraic equations.

         aH₂SO₄   +    bNH₄OH    →     c(NH₄)₂SO₄   +    dH₂O

a,b,c and d are simple coefficients that will balance the equation:

   Conservation of H: 2a + 5b = 8c + 2d

                               S:   a = c

                               O:  4a + b = 4c + d

                               N:   b = 2c

lets assume that a = 1

                             c= 1

                             b = 2

                  Solving for d from 4a + b = 4c + d

                   d = 4a + b -4c = 4(1) + 2 - 4(1) = 2        

 

                  H₂SO₄   +    2NH₄OH    →     (NH₄)₂SO₄   +    2H₂O

Learn more:

Balancing of equations brainly.com/question/6078553

#learnwithBrainly

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Answer : The number of moles of NO_2 gas added must be, 1.59 moles.

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

The given equilibrium reaction is,

                        SO_2(g)+NO_2(g)\rightleftharpoons SO_3(g)+NO(g)

Initial conc.    2.86               x             0          0

At eqm.       (2.86-1.30)    (x-1.30)     1.30     1.30

The expression of K_{eq} will be,

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Now put all the given values in this expression, we get:

3.70=\frac{(1.30)\times (1.30)}{(2.86-1.30)\times (x-1.30)}

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Thus, the number of moles of NO_2 gas added must be, 1.59 moles.

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